Definite integral involving rational function and 𝜋

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I have tried to solve this integration but i can't, can somebody figure out a way to do this..
 
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Typically , for these types of problem. A good technqie to think about is u-substitution and let u be the more complicated function.
 
ahilan said:
I have tried to solve this integration but i can't, can somebody figure out a way to do this..
Two techniques should be applied in this case. The first one is the substitution as proposed in post #2, and the second one is the integration by partial fractions. The order in which techniques should be used first is irrelevant. If the integration by partial fractions is used first, there will be the next equation. $$ \int_{0}^{\sqrt{\pi-1}}\frac{16\pi^2x^3}{(x^2+\pi+1)^3}dx=\int_{0}^{\sqrt{\pi-1}}\frac{16\pi^2x}{(x^2+\pi+1)^2}dx-\int_{0}^{\sqrt{\pi-1}}\frac{16\pi^3x}{(x^2+\pi+1)^3}dx-\int_{0}^{\sqrt{\pi-1}}\frac{16\pi^2x}{(x^2+\pi+1)^3}dx $$
 
Gavran said:
Two techniques should be applied in this case. The first one is the substitution as proposed in post #2, and the second one is the integration by partial fractions.
After the proposed u-substitution, the partial fractions step is trivial. In any case, it must be much simpler to do the u-substitution first.