Deformation of a Loaded Axial Beam

[Precursor]

Homework Statement
[PLAIN]http://img826.imageshack.us/img826/8600/217yf.jpg


The attempt at a solution
This is my work for part (a):

$$\delta = \frac{PL}{AE}$$

$$\delta = \frac{(6*10^3 N)(0.4 m)}{(70*10^9 Pa)(\frac{\pi}{4})(0.02^2 m)}$$

$$\delta = 0.1091 mm$$

However, the solution for this is actually 0.01819 mm. Where did I go wrong?

 

[pongo38]

I think you have found the movement of A relative to B. I expect the answer is the movement of A relative to C.