Degree of a Map: Finding Antipodal Points for Odd Degree Functions

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The discussion focuses on two main questions related to the degree of maps between spheres. The first question involves proving that the degree of the composition of two functions equals the product of their degrees, with participants exploring the significance of counting preimages and their signs. The second question addresses the existence of antipodal points mapped to each other by an odd-degree function, with suggestions including fixed point theorems and examining the relationship between points and their antipodal counterparts. Participants express uncertainty about the connection between odd-degree functions and antipodal mappings but acknowledge that odd degree is a necessary condition for such mappings. The conversation highlights the complexity of rigorously proving these concepts in topology.
kbfrob

Homework Statement


Two questions: 1) Show that deg(f(g(x)) = deg(f)*deg(g)
2) f: Sn -> Sn
deg(f) is odd
then show there exists a pair of antipodal points that are mapped to antipodal points



The Attempt at a Solution


1) I have tried the method of just counting preimages, but i don't think this is the right direction. i know intuitively the deg of map between spheres is how many times you "wrap" the sphere around, and what i trying to show supports this, but i don't know how to show it rigorously.

2) We are dealing with antipodal maps in class, so i am trying to use them, but i have no idea how to use the fact that the degree of f is odd. i don't recall there being any fundamental difference between a map of odd and even degree.
 
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kbfrob said:
1) I have tried the method of just counting preimages, but i don't think this is the right direction.
What doesn't work about it?
 
it doesn't take into account the sign of the dervative at each of the preimages. in other words, the degree is not just the number of preimages. I'm not sure how to reconcile this.
 
kbfrob said:
it doesn't take into account the sign of the dervative at each of the preimages. in other words, the degree is not just the number of preimages. I'm not sure how to reconcile this.
Well, what if you count preimages together with their sign? Or modify the maps so that they have positive derivative at each preimage?
 
alright i got it. thank you very much.

any ideas on the second question?
i don't even know how to start.
 
kbfrob said:
alright i got it. thank you very much.

any ideas on the second question?
i don't even know how to start.
Nothing seems obvious to me. I suspect if I knew the content of the current chapter / previous couple chapters, something would leap out at me!

My best ideas at the moment are:
1. Try and apply some sort of fixed point theorem
2. Say something clever involving the quotient map Sn --> Sn / ~, where ~ is the relation that identifies antipodal points
3. Study some gadget that measures how different f(x) and f(-x) are from being antipodal (using -x to denote the point antipodal to x)

It's easy to see that odd degree is a necessary condition -- consider the standard maps f(\theta) = k \theta of degree k on the circle.
 
If f is a function of odd degree, mapping Sn to Sn, A(p) be the function that maps each point to its antipodal point and look at f(p)- f(A(p)).
 

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