Degrees Celcius to Farenheight, Conversion issues

[Nellen2222]

Degrees celsius to Farenheight, Conversion issues !

Homework Statement

You work in a materials testing lab ad your boss tells you to increase the temperature of a sample by 41.7 degrees celsius. Theo nly thermometer you can find at your workbench reads in degrees fahrenheit. If the initial temperature of the sample is 68.2 degrees farenheight, what is its temperature in degrees farenheight when the desired temperature increase has been achieved?

Homework Equations

F degrees = (1.8*C) + 32

The Attempt at a Solution

Tried changing 41.1 degrees celsius into fareneheight and got 107.06. Added that to the initial degrees and got 175.26 Farenheight. However, the answer is still wrong. (3 sig dig rounded to its actually 175.. not that the answer is correct)

What am i doing wrong?

 

[Dickfore]

Homework Statement

You work in a materials testing lab ad your boss tells you to increase the temperature of a sample by 41.7 degrees celsius. Theo nly thermometer you can find at your workbench reads in degrees fahrenheit. If the initial temperature of the sample is 68.2 degrees farenheight, what is its temperature in degrees farenheight when the desired temperature increase has been achieved?

Homework Equations

F degrees = (1.8*C) + 32

The Attempt at a Solution

Tried changing 41.1 degrees celsius into fareneheight and got 107.06. Added that to the initial degrees and got 175.26 Farenheight. However, the answer is still wrong. (3 sig dig rounded to its actually 175.. not that the answer is correct)

What am i doing wrong?

Degrees Celsius/Fahrenheit is not the same as Celsius/Fahrenheit degrees. This is a sentence whose meaning is that there is a difference between a given temperature, and a temperature difference. Your equation is actually valid only for given temperatures. For temperature intervals, you need:
$$\begin{array}{l}<br /> \frac{t_1}{\mathrm{^{o}F}} = \frac{9}{5} \, \frac{t_1}{\mathrm{^{o}C}} + 32 \\<br /> <br /> \frac{t_2}{\mathrm{^{o}F}} = \frac{9}{5} \, \frac{t_2}{\mathrm{^{o}C}} + 32<br /> \end{array}$$
$$\frac{t_2 - t_1}{\mathrm{F^{o}}} = \frac{9}{5} \, \frac{t_2 - t_1}{\mathrm{C^{o}}}$$

Notice the different placement of the "^o" symbol. One denotes degrees Celsius/Fahrenheit (current temperature), and the other denotes Celsius/Fahrenheit degrees (temperature interval).

 

[lewando]

A change of 1°F equals a change of 1.8°C.

 

[CWatters]

You work in a materials testing lab ad your boss tells you to increase the temperature of a sample by 41.7 degrees celsius. The only thermometer you can find at your workbench reads in degrees fahrenheit. If the initial temperature of the sample is 68.2 degrees farenheight, what is its temperature in degrees farenheight when the desired temperature increase has been achieved?

The equation for converting C to F can't be used to convert ΔC to ΔF directly.

Try converting 68.2F to C, add 41.7C and convert it back.

 

[Chestermiller]

If F = 1.8 C + 32, then

ΔF = 1.8 Δ C

What is ΔF if ΔC = 41.1?

 

[skeptic2]

Homework Equations

F degrees = (1.8*C) + 32

This equation is wrong for converting temperature differences from Celsius to Fahrenheit. Do not add the 32 deg. While Celsius degrees are 1.8 deg. larger than Fahrenheit degrees, the 32 degrees only provide and offset to align the two scales.