Delta Dirac: $\phi=-\pi+\epsilon$

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if [tex]\phi[/tex] is a angular coordinate , between ([tex]-\pi,\pi[/tex])

¿how much is [tex]\delta(\phi-\pi)[/tex] with [tex]\phi=-\pi+\epsilon[/tex]?
 
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The Dirac delta function yield zero unless it's argument is zero, in which case it yields 1 (this is an oversimplification, but it should do for the present discussion). In your case, the argument of the delta function is [tex]-2*\pi + \epsilon[/tex], so it should be zero. Did you mean to type, [tex]\phi=\pi + \epsilon[/tex]? In that case, the argument of the delta function would be just [tex]\epsilon[/tex], and then you need to get a bit more specific about how you are defining the delta function. Have you looked at this thread? https://www.physicsforums.com/showthread.php?t=73447
 
SpectraCat said:
The Dirac delta function yield zero unless it's argument is zero, in which case it yields 1 (this is an oversimplification, but it should do for the present discussion). In your case, the argument of the delta function is [tex]-2*\pi + \epsilon[/tex], so it should be zero. Did you mean to type, [tex]\phi=\pi + \epsilon[/tex]? In that case, the argument of the delta function would be just [tex]\epsilon[/tex], and then you need to get a bit more specific about how you are defining the delta function. Have you looked at this thread? https://www.physicsforums.com/showthread.php?t=73447

then the dirac delta evaluated in (-2pi+epsilon) is 0 or infinite?
 
specifically, i need to find T, in the follows equation:

[tex]\delta(\phi-\pi)+k=T\delta(\phi-\pi)[/tex]
where [tex]\phi[/tex] is between ([tex]-\pi,\pi[/tex])
 
With that specific range the delta distribution is zero; phi can't become equal to pi. So you get the equation 0 + k = T*0.
 
haushofer said:
With that specific range the delta distribution is zero; phi can't become equal to pi. So you get the equation 0 + k = T*0.

but, if i do:

[tex]\int^{\pi-\epsilon}_{-\pi+\epsilon}\delta(\phi-\pi)d\phi+\int^{\pi-\epsilon}_{-\pi+\epsilon} k=T\int^{\pi-\epsilon}_{-\pi+\epsilon}\delta(\phi-\pi)[/tex]

is correct??

pd: [tex]\phi[/tex] can be equal to [tex]\pi[/tex]...[tex]\phi[/tex] is between [tex](-\pi,\pi)[/tex]
 
Last edited:
You want to integrate from pi-epsilon to pi+epsilon. That will include the relevant range of the dirac delta.