Delta function defined for complez values

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SUMMARY

The Dirac delta function can be extended to complex values, specifically in forms such as δ(x - a - bi) and δ(-ix). However, the convergence of test functions in these cases is problematic, as they yield infinite results. It is established that δ(ix) can be defined as δ(x) due to the modulus of 'i' being one. The delta function is primarily defined on the real line, and its application in complex scenarios must be approached with caution, particularly under integral signs.

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  • Understanding of the Dirac delta function and its properties
  • Familiarity with complex numbers and their operations
  • Knowledge of test functions in mathematical analysis
  • Basic principles of integration and scaling properties
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  • Study the implications of the delta function under integral signs
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mhill
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is there a form to define the dirac delta function for complex values ? i mean

[tex]\delta (x-a-bi)[/tex] or [tex]\delta (-ix)[/tex]

using 'test functgions' i get that they converge nowhere (always infinite) which makes no sense at all, using scalling properties we could define

[tex]\delta (ix) = \delta(x)[/tex] since modulus of 'i' is just one but i am not completely sure.
 
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mhill said:
is there a form to define the dirac delta function for complex values ? i mean

[tex]\delta (x-a-bi)[/tex] or [tex]\delta (-ix)[/tex]

using 'test functgions' i get that they converge nowhere (always infinite) which makes no sense at all, using scalling properties we could define

[tex]\delta (ix) = \delta(x)[/tex] since modulus of 'i' is just one but i am not completely sure.

In using the delta function, the domain is the real line. There is no problem with using it with a complex constant or even multiplying x by i. Just be careful about what problem you are trying to solve. Remeber the delta function makes sense only under integral signs.
 

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