Derivating a velocity's components

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SUMMARY

The discussion focuses on deriving the components of velocity from the equation v(t) = \dot{r}\hat{r} + r \dot{\hat{r}}. The user initially attempts to differentiate the equation but arrives at an incorrect expression for acceleration. The correct derivative is identified as \dot{v(t)} = (\ddot{r} - r \dot{\delta}^2) \hat{r} + (r \ddot{\delta} + 2\dot{r} \dot{\delta}) \hat{e}. The conversation emphasizes the importance of recognizing that the derivative of a vector is also a vector, incorporating both unit vectors and scalar components.

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Homework Statement



What is the derivate of the following equation?

[tex]v(t) = \dot{r}\hat{r} + r \dot{\hat{r}} = \dot{r} \hat{r} + r \dot{\delta} \hat{e}[/tex]

where e is dependent on the angle, delta.

The Attempt at a Solution



My answer:

We know that
[tex]\hat{r} = \frac {r} {|r|}[/tex]

=> [tex]\hat{r} = \frac {r} {|r|}[/tex]

=> [tex]D( \dot{r} \hat{r} ) = \ddot{r} \hat{r} + \dot{r} \dot{ \hat{r}}[/tex]
=> [tex]D( r \dot{\hat{r}} ) = \dot{r} \dot{\hat{r}} + \frac {r \ddot{r} } {|r|}[/tex]

so we get

[tex]a(t) = \hat{r} ( \ddot{r} ) + 2 \dot{r} \dot{ \hat{r}} + \frac {r \ddot{r}} {|r|}[/tex]

which is wrong.

The correct answer is

[tex]\dot{v(t)} = (\ddot{r} - r \dot{\delta}^2) \hat{r} + (r \ddot{\delta} + 2\dot{r} \dot{\delta}) \hat{e}[/tex]
 
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Are you working with vectors or scalars?
 
foxjwill said:
Are you working with vectors or scalars?

The derivate of a vector is a vector.
It consists of unit vectors which means that there is too scalars in the unit vectors.
So I am working with vectors.
 

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