Undergrad Derivation for the indicial exponent in the Frobenius method

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The discussion centers on a derivation involving the Frobenius method, specifically focusing on the indicial exponent in the context of asymptotic methods and perturbation theory. The user expresses difficulty in understanding a specific equation, 3.3.3b, which involves the function y(x) expressed as A(x)*(x-x0)^α, with A(x) expanded in a Taylor series. The conversation highlights the use of series multiplication to derive coefficients, emphasizing the need for clarity in the summation process. Participants aim to clarify the steps involved in the derivation and the implications of the indicial exponent. Overall, the discussion seeks to demystify the mathematical techniques used in this context.
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I'm reading a book called Asymptotic Methods and Perturbation Theory, and I came across a derivation that I just couldn't follow. Maybe its simple and I am missing something. Equation 3.3.3b below. y(x) takes the form A(x)*(x-x0)^α and A(x) is expanded in a taylor series.

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Use \begin{split}<br /> \left(\sum_{n=0}^\infty a_nx^n \right)\left(\sum_{n=0}^\infty b_nx^n \right) &amp;= <br /> \sum_{n=0}^\infty \sum_{m=0}^\infty a_n b_m x^{n+m} \\<br /> &amp;=\sum_{k=0}^\infty \left(\sum_{n=0}^n a_n b_{k-n}\right) x^k. \end{split}
 

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