Derivation of an expression for centripetal acceleration

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SUMMARY

The discussion centers on deriving the expression for centripetal acceleration of a satellite orbiting Earth. The user successfully derived the velocity of the satellite as v = √(GM/r) and then equated the gravitational force F = Gm1m2/r² with the centripetal force F = mv²/r. This led to the conclusion that the centripetal acceleration is given by GM/r². The derivation was confirmed as correct by another participant in the forum.

PREREQUISITES
  • Understanding of gravitational force equations, specifically F = Gm1m2/r²
  • Knowledge of centripetal force and acceleration concepts, particularly F = mv²/r
  • Familiarity with algebraic manipulation of equations
  • Basic knowledge of orbital mechanics
NEXT STEPS
  • Study the derivation of orbital mechanics principles, focusing on Kepler's laws
  • Learn about the implications of centripetal acceleration in different gravitational fields
  • Explore the relationship between gravitational force and orbital velocity in more complex systems
  • Investigate the effects of satellite mass and radius on orbital dynamics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and orbital dynamics, as well as educators looking for clear examples of gravitational and centripetal force relationships.

Sophieg

Homework Statement


I have derived the expression for the velocity of the satellite v= root of GM/r however I'm struggling to derive an expression for the centripetal acceleration of a satellite orbiting Earth.

Homework Equations

The Attempt at a Solution


I'm not entirely sure which equations to relate or equate. To find the velocity I equated the force between two masses and the centripetal force and rearranged.
 
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update: I think I've worked it out..:sorry: I equated the equation for centripetal force F=mv^2/r (of the planet) to the force between the two masses (planet and the satellite) to get:
- Gm1m2/r^2 = mv^2/r ... canceled a mass from either side and obtained Gm/r^2=v^2/r and since v^2/r = centripetal acceleration then the answer is GM/r^2?
Is this correct?
Thanks in advance! :wink:
 
Hi sophleg. Welcome to PF!

Your answer is correct but I am a bit puzzled by how you determined that ##v = \sqrt {GM/r}## before working out the centripetal acceleration.

AM
 
Hello Andrew,

Thank you!

I equated the force between two masses F=Gm1m2/r^2 = centripetal force F=mv^2/r and rearranged for v!
 

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