Derivation of equation of motion from various forces.

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SUMMARY

The discussion focuses on deriving the equations of motion for a particle subjected to various forces, specifically using second-order ordinary differential equations (ODEs). The forces considered include F(x, t) = k(x + t²), F(x', t) = kx²x', and others, with initial conditions set at t = 0. Participants noted that while part (a) was straightforward, parts (b) through (e) presented significant challenges due to their nonlinear nature. The discussion highlights the complexity of solving for x(t) in these scenarios, particularly in part (b), where the integral leads to complicated expressions involving arctangent and logarithmic functions.

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Homework Statement



A particle of mass m is acted on by the forces as given below. Solve these equations
to find the motion of the particle in each case.

(a) F(x, t) = k(x + t2), with x = x0 and v = v0 = 0 when t = 0;
(b) F(x', t) = kx^2 x', with x = x0 and v = v0 = 0 when t = 0;
(c) F(x', t) = k(ax'+ t), with v = v0 when t = 0;
(d) F(x, x') = ax^2/x';
(e) F(x, x', t) = k(x + x't).

(a) I didn't have any trouble with as it was just a simple non homogeneous 2nd order ODE. The others to me seemed nonlinear and very difficult for some reason. I'm wondering how the variables which F is dependent on might affect the problems and if there is some method for solving these kinds of ODE's. Also my professor said that for each one to solve for x(t).
 
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In part (b) I get as far as solving for v(t), but to solve for x(t) I'm left with the integral of (1/(x^3 + x0^3)). Is very messy and ends up being tan-1(some function of x) + ln(another function of x). Because of that I can't solve for just x in terms of only t.
 
For part (b), what is F(t=0)?...If the force on the particle is proportional to the speed, and its initial speed is zero, will the particle ever actually go anywhere?
 

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