Derivation of Laplace in spherical co-ordinates

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Homework Help Overview

The discussion revolves around the derivation of the Laplace operator in spherical coordinates, specifically focusing on a particular equation involving the derivative of a function with respect to one of the spherical coordinates. Participants are sharing their attempts and resources related to this mathematical topic.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various methods for deriving the Laplace operator, including the use of the action principle and transformations of coordinates. Some express uncertainty about the derivation process and seek clarification on specific equations.

Discussion Status

There is an ongoing exchange of ideas, with some participants providing hints and suggestions for approaching the derivation. Others express their challenges and seek further assistance, indicating a collaborative effort to understand the topic better.

Contextual Notes

Some participants question whether the original poster has the necessary background in partial differential equations, which may impact their ability to follow the discussion. The original poster has also shared attachments with basic equations, indicating a reliance on external materials for guidance.

darwined
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I have been trying to derive the Laplace in spherical co ordinates.
I have attached a file which has basic equations.
I am trying to get the following equation.

d(phi)/dx= -sin(phi)/(r sin (theta)).

I have also attached the materials I am referring to.
Can someone please help me derive the equation.

Thank you.
 

Attachments

  • Laplac.jpg
    Laplac.jpg
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  • derivation of the Laplacian from.pdf
    derivation of the Laplacian from.pdf
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  • The Laplacian Operator from Cartesian to Cylindrical to Spherical Coordinates.pdf
    The Laplacian Operator from Cartesian to Cylindrical to Spherical Coordinates.pdf
    316.7 KB · Views: 659
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This is a pretty cumbersome way. The most easy is to use the action principle. The action
A[\phi]=\int \mathrm{d}^3 \vec{x} [(\vec{\nabla} \phi)^2+f \phi]
leads to the equation
\Delta \phi=f.
Now you write the gradient in terms of spherical coordinates (which is easy to derive by your direct method)
\vec{\nabla} \phi=\vec{e}_r \partial_r \phi+\frac{1}{r} \vec{e}_{\theta} \partial_{\theta} \phi + \frac{1}{r \sin \theta} \vec{e}_{\varphi} \partial_{\varphi} \phi.
The volume element is
\mathrm{d}^3 {\vec{r}}=\mathrm{d} r \mathrm{d} \theta \mathrm{d} \varphi r^2 \sin \theta.
This you plug into the action integral and use the Euler-Lagrange equations to derive the field equation in terms of spherical coordinates. This leads to the Laplacian by identifying it with f[/tex].
 
darwined said:
I have been trying to derive the Laplace in spherical co ordinates.
I have attached a file which has basic equations.
I am trying to get the following equation.

d(phi)/dx= -sin(phi)/(r sin (theta)).

I have also attached the materials I am referring to.
Can someone please help me derive the equation.

Thank you.
Show us your attempt at deriving that equation.
 
I second Vela. Vanhees is focusing on ##\Delta##. If you want a hint for your ## {d\phi \over dx} ## question: ##\tan \phi = {y \over x} ## is a good starting point.
 
Thank you for your reply vanhees71. But I am not sure how you even got the equation.

A[ϕ]=∫d3x→[(∇→ϕ)2+fϕ]

I am a beginner trying to learn this derivation.

Thank you BvU, your idea helped.

Thank you all.
 
Your attached references are just a straightforward transformation of coordinates that you learn how to do in a course on partial differential equations. Have you had a course that covers partial differential equations yet?

Chet
 

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