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Derivation of y(x,t)=Asin(kx-wt)

  1. Oct 7, 2009 #1

    morrobay

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    Gold Member

    Can someone show, or explain with a diagram, how y(x,t)=Asin(kx-wt)
    is a solution of the wave equation. In particular how for a given (y) value that
    (kx-wt) is a constant.
     
  2. jcsd
  3. Oct 8, 2009 #2
    This isn't the full solution. The full solution is a superposition of solutions
    Asin(kx - wt + C), with different A's, k's, w's and C's, subject only to w/k=
    (propagation speed of wave)

    I don't understand this at all. y depends on x and t, and so does (kx-wt)
     
  4. Oct 8, 2009 #3

    Vanadium 50

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    Staff Emeritus
    Science Advisor
    Education Advisor

    If y and A are constant, so is arcsine(y/A). That should get you going.
     
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