- #1

Eitan Levy

- 259

- 11

- Homework Statement
- There is an electromagnetic wave with a magnetic component equal to:

Bsin(ax+by-3*sqrt(5)*10^6*t)(2x/3-y/3-2z/3) (The second set of parentheses represent the direction of the wave)

What is ω for this wave?

- Relevant Equations
- ω=kv

I am quite confused by this. I was sure that ω=3*sqrt(5)*10^6, because that is the coefficient of t, and generally u(x,y,z,t)=Asin(kx−ωt+ϕ) for a multi dimensional harmonic wave.

However in the answers it is said that ω=3*sqrt(5)*10^14. I can't see the reason for that, could anyone explain please?

However in the answers it is said that ω=3*sqrt(5)*10^14. I can't see the reason for that, could anyone explain please?