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Derivative of 10 - 20/(t+1)^2 - process help

  1. Feb 13, 2012 #1

    939

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    1. The problem statement, all variables and given/known data

    Derivative of

    10 - 20/(t+1)^2. It's hard to write but basically 10 is IN FRONT of the equation, it's NOT 10-20 together, over (t+1)^2. 10 is seperate and is in front of the equation.

    2. Relevant equations

    10 - 20/(t+1)^2

    3. The attempt at a solution

    My main question is the process. Do you find the derivative of - 20/(t+1)^2, and then put 10 in front of the equation? Or do you multiply the derivative of it by 10?
     
  2. jcsd
  3. Feb 13, 2012 #2

    eumyang

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    Homework Helper

    First, what you wrote is not an equation. It's an expression.
    Do you mean this?
    [tex]f(x) = 10 - \frac{20}{(t+1)^2}[/tex]
    If you mean the above, then no. You find the derivative of 10, and then subtract the derivative of the fraction. The difference rule applies (derivative of f - g = f' - g').

    EDIT: Or do you mean this?
    [tex]f(x) = 10\frac{-20}{(t+1)^2}[/tex]
     
  4. Feb 13, 2012 #3

    939

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    Thanks a lot for the help. And I meant this one.
     
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