Derivative of 10 - 20/(t+1)^2 - process help

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SUMMARY

The discussion centers on finding the derivative of the expression f(t) = 10 - 20/(t+1)^2. Participants clarify that the constant 10 is separate from the fraction and emphasize the application of the difference rule in differentiation. The correct approach involves calculating the derivative of the constant (which is zero) and then subtracting the derivative of the fraction -20/(t+1)^2. The final derivative is f'(t) = 0 - (-40/(t+1)^3), simplifying to 40/(t+1)^3.

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Homework Statement



Derivative of

10 - 20/(t+1)^2. It's hard to write but basically 10 is IN FRONT of the equation, it's NOT 10-20 together, over (t+1)^2. 10 is separate and is in front of the equation.

Homework Equations



10 - 20/(t+1)^2

The Attempt at a Solution



My main question is the process. Do you find the derivative of - 20/(t+1)^2, and then put 10 in front of the equation? Or do you multiply the derivative of it by 10?
 
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939 said:

Homework Statement



Derivative of

10 - 20/(t+1)^2. It's hard to write but basically 10 is IN FRONT of the equation, it's NOT 10-20 together, over (t+1)^2. 10 is separate and is in front of the equation.
First, what you wrote is not an equation. It's an expression.
Do you mean this?
[tex]f(x) = 10 - \frac{20}{(t+1)^2}[/tex]
939 said:
My main question is the process. Do you find the derivative of - 20/(t+1)^2, and then put 10 in front of the equation? Or do you multiply the derivative of it by 10?
If you mean the above, then no. You find the derivative of 10, and then subtract the derivative of the fraction. The difference rule applies (derivative of f - g = f' - g').

EDIT: Or do you mean this?
[tex]f(x) = 10\frac{-20}{(t+1)^2}[/tex]
 
eumyang said:
First, what you wrote is not an equation. It's an expression.
Do you mean this?
[tex]f(x) = 10 - \frac{20}{(t+1)^2}[/tex]

Thanks a lot for the help. And I meant this one.
 

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