The discussion centers around finding the derivative of the function f(x) = 1/4 sin^2 2x, which involves trigonometric functions and differentiation techniques.
Some guidance has been offered regarding a potential oversight in the differentiation process, specifically the factor of 2 that may have been missed. The discussion reflects an ongoing exploration of the differentiation steps without reaching a final consensus.
Participants are working under the constraints of homework guidelines, which may limit the extent of assistance provided. There is an acknowledgment of a potential misunderstanding in the application of differentiation rules.
(Above) This is f(x), not f'(x).Bashyboy said:Homework Statement
Find the derivative of f(x) = 1/4 sin^2 2x
The Attempt at a Solution
f'(x) =1/4(sin 2x)^2
Bashyboy said:f'(x) = 1/4*2(sin 2x)(cos 2x)
f'(x) = 1/4(sin 4x)
That is my answer to the problem, but the book has it as f'(x) = 1/2(sin 4x)
What did I do wrong?