Derivative of A Trigonometric Function

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Bashyboy
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Homework Statement


Find the derivative of f(x) = 1/4 sin^2 2x


Homework Equations





The Attempt at a Solution



f'(x) =1/4(sin 2x)^2

f'(x) = 1/4*2(sin 2x)(cos 2x)

f'(x) = 1/4(sin 4x)

That is my answer to the problem, but the book has it as f'(x) = 1/2(sin 4x)
What did I do wrong?
 
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Oh, yes, thank you.
 
Bashyboy said:

Homework Statement


Find the derivative of f(x) = 1/4 sin^2 2x

The Attempt at a Solution


f'(x) =1/4(sin 2x)^2
(Above) This is f(x), not f'(x).
Bashyboy said:
f'(x) = 1/4*2(sin 2x)(cos 2x)

f'(x) = 1/4(sin 4x)

That is my answer to the problem, but the book has it as f'(x) = 1/2(sin 4x)
What did I do wrong?