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## Homework Statement

Find g' (-1/2), where g(x) is the inverse of f(x) = x

^{3}/ (x

^{2}+ 1)

## Homework Equations

g'(x) = 1/f' [g(x)]

## The Attempt at a Solution

Everything else I tried got really messy, but I feel like I'm going out on a limb by:

1) y=x

^{3}/ (x

^{2}+1)

2) y=x

^{3}x

^{-2}/ 1

3) y=x

4) g '(0.5)= 1/ (0.5

^{3}/(0.5

^{2}+1) = 10

I don't even know if I'm going about it the right way. Any help would be awesome. Thanks.