Penultimate
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[tex]\sqrt{x^2+y^2}[/tex]=2arctg[tex]\frac{y}{x}[/tex]
Dont know where to start with this one either.
Dont know where to start with this one either.
The discussion revolves around finding the derivative of the equation \(\sqrt{x^2+y^2}=2\arctan\left(\frac{y}{x}\right)\), with participants exploring the context of implicit differentiation and the roles of the variables involved.
The discussion is ongoing, with various participants attempting to clarify the problem's requirements and expressing their confusion about the differentiation process. Some guidance has been offered regarding the chain rule and the nature of the derivative being sought, but no consensus has been reached on the approach.
There is a lack of clarity regarding whether the derivative should be taken with respect to \(x\) or if partial derivatives are needed, which has led to differing interpretations among participants.
Simply saying "Do the derivate" (or derivative) isn't sufficient. The derivatie with respect to what variable? Is the problem to find partial derivatives of that with respect to x and y or are we to assume that y is a function of x and you wish to find dy/dx?Penultimate said:[tex]\sqrt{x^2+y^2}[/tex]=2arctg[tex]\frac{y}{x}[/tex]
Dont know where to start with this one either.
So far you haven't shown that you are even trying. What have you done?Penultimate said:I know is something with derivating twice but i am not figuring anything out.
No, the exercise asks for the derivative, dy/dx, not the differential.Penultimate said:The exercise requires the differential of the expression. I think that is dy/dx.
No, you don't need to differentiate twice. Once will be enough to find the derivative, but you will need to use implicit differentiation.Penultimate said:I know is something with derivating twice but i am not figuring anything out.