Derivative of the cross and dot product

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Homework Help Overview

The discussion revolves around proving the derivatives of the dot and cross products of two functions, A(t) and B(t), with respect to a variable t. Participants are exploring the differentiation of these vector operations and the application of product rules in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using the product rule for differentiation of the dot product and suggest similar reasoning for the cross product. Some mention the potential complexity of using advanced notation, while others propose working backward from the expressions to simplify the process.

Discussion Status

The discussion is active, with participants sharing different perspectives on how to approach the problem. There is acknowledgment of previously proven derivative rules, and some guidance is offered regarding the methods to apply, though no consensus has been reached on a singular approach.

Contextual Notes

One participant notes their limited experience with differentiating these products, indicating a potential gap in foundational understanding that may influence the discussion. There is also mention of the complexity of advanced mathematical notation, which may affect the participants' comfort level with the topic.

bluelagoon
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Homework Statement



If you have two functions dependent on t, A(t) and B(t). Prove their derivatives are as follows:

d(A (dot) B) / dt = [A (dot) (dB)/(d(t)] + [d(A)/d(t) (dot) B]

{Where "(dot)" acts as the dot product}




d(A x B) / dt = [A x (dB)/(d(t)] + [d(A)/d(t) x B]

{Where "x" acts as the cross product}




I have little experience with differentiating cross products and dot products and appreciate any help in starting this one!

Thanks,
Janet
 
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Well A . B = axbx + ayby + azbz (in 3 dimensions)
Differentiate that using the product rule, then regroup and show that its the expression you need it to be equal to. The cross product is similar.
 
I think the easy way around of using [tex]\delta_{ij}[/tex] and [tex]\epsilon_{ijk}[/tex] is a bit too advanced.

For the cross-product I would just say from experience that working backward may be a bit less confusing, e.g. show what two parts are and simplify the output expression, and then showing that it is equal to the derivative of the initial expression
 
You've already proven the derivative rule for one kind of product; doesn't the same method work for these products?
 

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