Derivative of the magnitude of a function

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The discussion centers on the derivative of the magnitude of a function, specifically the expression d/dx|r(t)|=1/|r(t)| X r(t)*r'(t). This formula relates the derivative of the position vector r(t) to its magnitude, highlighting that the sign of r(t) affects the derivative's outcome. When r(t) is positive, the derivative simplifies to the standard form, while a negative r(t) introduces a negative sign in the calculation. The participants emphasize the importance of differentiating |r(t)|, which is defined as the square root of the dot product of r(t) with itself. Overall, the discussion clarifies the mathematical relationship between a vector's magnitude and its derivative.
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I just learned that d/dx|r(t)|=1/|r(t) |X r(t)*r'(t), where * is the dot product and X is mutiply. What is the meaning of this statement, especially in relation to d/x r(t)=r'(t)?(Lets say r(t) is the position vector equation.)
 
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##\frac{r(t)}{|r(t)|}## is just the sign of r(t). If r(t) is positive, it is +1 and you simply get the regular derivative. If r(t) is negative, |r(t)|=-r(t) and this fraction gives the correct minus sign.
 
Recall that ## |r(t)| = \sqrt {r(t) \cdot r(t)} ##. Differentiate this.
 
voko said:
Recall that ## |r(t)| = \sqrt {r(t) \cdot r(t)} ##. Differentiate this.
A simpler starting point might be to write:

## |r(t)|^2 = r(t) \cdot r(t) ##

Chet
 

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