Solve d2y/dx3: Step-by-Step Guide

  • Thread starter Thread starter baba_944
  • Start date Start date
  • Tags Tags
    Derivative
Click For Summary
The discussion revolves around the confusion regarding the notation d2y/dx3, which is clarified as the second derivative of y with respect to x (d^2y/dx^2) and the third derivative of y with respect to x (d^3y/dx^3). Participants suggest checking for typos in the source material or consulting a teacher for clarification. The original poster acknowledges a misunderstanding and confirms they are self-teaching. The conversation emphasizes the importance of understanding derivative notation in calculus. Overall, accurate interpretation of mathematical notation is crucial for solving related problems.
baba_944
Messages
8
Reaction score
0

Homework Statement


[/B]
I've tried to search this up but to no avail. How am I suppose to solve this:

d2y/dx3

Homework Equations


N/A

The Attempt at a Solution



Here's what I think I need to do:

1: Square and cube y and x respectively.
2: Find the second and third derivative of y and x respectively.

Thank you.
 
Physics news on Phys.org
This looks like a typo, I think you need to ask your teacher what they want here or of course you could compute the ##d^2y/dx^2## and the ##d^3y/dx^3##

The superscripts aren't powers and these aren't fractions of differentials.

The notation means:
- 2nd derivative of y with respect to x for ##d^2y/dx^2## and
- 3rd derivative of y with respect to x for ##d^3y/dx^3##

Check to see if your book has an errata sheet online which would indicate whether its a typo that is if this came from your book otherwise check with your teacher.
 
Last edited:
Human error on my behalf. I mistype it. But yeah, thank you. I'm self-teaching (as scary enough as it is, ha ha) so no teacher besides myself

So basically it means to take the second (or nth) derivative? Thank you. .
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
9
Views
2K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K