Second-Order separable Differential equations

[Woolyabyss]

Homework Statement

Solve d2y/dt2 = dx/dt2, if x = 0 and dx/dt = 1 when t = 0

Homework Equations

The Attempt at a Solution

d2y = dx

I'm not exactly sure what to do here the fact that dt2 is under the denominator for both fractions is confusing memaybe its a typo? should it be d2y/dx2 = dx/dt?

 

[Mark44]

Homework Statement

Solve d2y/dt2 = dx/dt2, if x = 0 and dx/dt = 1 when t = 0

Homework Equations

The Attempt at a Solution

d2y = dx

I'm not exactly sure what to do here the fact that dt2 is under the denominator for both fractions is confusing memaybe its a typo? should it be d2y/dx2 = dx/dt?

That has to be a typo. dx/dt² makes zero sense.

On a side note, try to make you posts clearer by at least indicating that some things are exponents. The simplest way is to use the caret or circumflex character (^), which is pretty much universally used for this purpose. For example, 3x² and e^(rt).

A little nicer is to use the advanced menu (click Go Advanced below the input area. For exponents, click the X² button. You can do subscripts with the X₂ button.

For fancier stuff, you can use LaTeX to write things like $10x^2$ and even fancier stuff. Here's a link to a summary of how to do that: https://www.physicsforums.com/showthread.php?t=617567 - item 2 on the list.

 

[Woolyabyss]

That has to be a typo. dx/dt² makes zero sense.

On a side note, try to make you posts clearer by at least indicating that some things are exponents. The simplest way is to use the caret or circumflex character (^), which is pretty much universally used for this purpose. For example, 3x² and e^(rt).

A little nicer is to use the advanced menu (click Go Advanced below the input area. For exponents, click the X² button. You can do subscripts with the X₂ button.

For fancier stuff, you can use LaTeX to write things like $10x^2$ and even fancier stuff. Here's a link to a summary of how to do that: https://www.physicsforums.com/showthread.php?t=617567 - item 2 on the list.

Alright thanks, If i were to assume they meant d^2y/dt^2 = dx/dt

would I be correct in saying I could integrate both sides and it would be dy/dt = x + c?

 

[Mark44]

It might be better to figure out what the exact problem should be. Can you contact your instructor to get this clarified?

 

[Woolyabyss]

It might be better to figure out what the exact problem should be. Can you contact your instructor to get this clarified?

No I am afraid not I'll just leave ut for now. Thans anyway

 

[HallsofIvy]

The difficulty is that you have a single equation for two unknown functions, x and y. That is not sufficient. You need another equation.