Derive equations for Electric Field/Electric Potential

Click For Summary
SUMMARY

The discussion focuses on deriving equations for the electric potential and electric field generated by a charged ring with charge Q and radius R, positioned in the yz-plane. The electric potential at a distance x above the center of the ring is expressed as V = kQ/(x² + R²)^(1/2). Subsequently, the electric field is derived as E = kQ/(x² + R²). The user successfully solved part (a) of the problem and clarified the derivation for part (b), ensuring the results are presented in vector form.

PREREQUISITES
  • Understanding of electric potential (V) and electric field (E) concepts
  • Familiarity with Coulomb's law and the constant k
  • Knowledge of vector notation in physics
  • Basic algebra and calculus for manipulating equations
NEXT STEPS
  • Study the derivation of electric fields from potential functions
  • Explore the concept of superposition in electric fields
  • Learn about the applications of electric fields in different geometries
  • Investigate the relationship between electric potential and electric field in three-dimensional space
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding electric fields and potentials in charged systems.

Renaldo
Messages
58
Reaction score
0

Homework Statement




(a)
A ring with charge Q and radius R is in the yz-plane and centered on the origin. What is the electric potential a distance x above the center of the ring? (Use any variable or symbol stated above along with the following as necessary: k.)

(b)
Derive the electric field from this relationship. (Use any variable or symbol stated above along with the following as necessary: k.)


Homework Equations



V = U/q
U = -qEr
E = kQ/r2

r = (x2+R2)0.5


The Attempt at a Solution



I got problem (a) correct. I combined the above equations which resulted in

kQ/r

kQ/(x2+R2)0.5

For (b), it wants the answer in i + j + k.

j and k are 0.

V = qEr/q
V = Er
E = V/r

E = kQ/r2

E = kQ/(x2+R2)

This is not the correct answer for i. The problem is due in 1 hour, 30 minutes.
 
Physics news on Phys.org
Well, it turns out that I was able to figure this one out just in time.
 

Similar threads

Replies
5
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 22 ·
Replies
22
Views
4K
Replies
11
Views
4K
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
2
Views
2K