Derive Sin(x+y) & Cos(x+y) Using Euler's Formula

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SUMMARY

The derivation of sin(x+y) and cos(x+y) can be accomplished using Euler's formula, which states that e^(ix) = cos(x) + i*sin(x). This method, while tedious, provides a straightforward approach to obtaining the expansions. Alternatively, the use of 2x2 rotation matrices, R(θ), where R(x)R(y) = R(x+y), offers a geometric perspective that aligns with Euler's formula but operates within R^2. For further insights, a proof can be found on Wikipedia, although it is not exhaustive.

PREREQUISITES
  • Understanding of Euler's formula and its application in complex numbers.
  • Familiarity with trigonometric identities and their expansions.
  • Basic knowledge of 2x2 rotation matrices and their properties.
  • Ability to manipulate complex numbers and perform algebraic operations.
NEXT STEPS
  • Study the derivation of trigonometric identities using Euler's formula in detail.
  • Explore the properties and applications of 2x2 rotation matrices in geometry.
  • Research the relationship between complex numbers and trigonometric functions.
  • Review proofs of trigonometric identities available on educational platforms like Wikipedia.
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Mathematicians, physics students, and anyone interested in understanding the derivation of trigonometric identities using advanced mathematical concepts.

Pseudo Statistic
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Can anyone tell me how to derive the sin(x+y) and cos(x+y) expansions? The ones that are like cos x sin y or sin y cos x + other stuff?
Preferrably, could this be derived with Euler's formula alone? Or something not too geometric? (All those OAs and OBs and XBs and XYs on geometric diagrams confuse me too much to follow)
Thank you.
 
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You could use Euler's formula. It is tedious, but straightforward.
 
Another way is to use the 2X2 rotation matrices R(\theta), which have R(x)R(y)=R(x+y). This is equivalent to using Euler's formula, only you're working in R^2 instead of the complex numbers.
 
There's a short proof at wikipedia, you can view it at the end of this page.
It is, however, not a completed proof, but you can get some ideas about proving it. :)
 

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