Deriving Equality with Binomials

  • Context: Graduate 
  • Thread starter Thread starter LuHell
  • Start date Start date
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 2K views
LuHell
Messages
1
Reaction score
0
Hi,

I am reading a paper and I am trying to understand an equality which is given without proof:
[tex]\sum_{k=1}^s\binom{2s-k}{s}\frac{k}{2s-k}v^k(v-1)^{s-k}=v\sum_{k=0}^{s-1}\binom{2s}{k}\frac{s-k}{s}(v-1)^{k}[/tex]
Here, s>0, k and v are positive integers.
The equality in question appears in Lemma 2.1 of
http://web.williams.edu/Mathematics.../graphs/mckay_EigenvalueLargeRandomGraphs.pdf

Would you be kind and give me some insights on how to derive this equality?

Thank you,

LH
 
Mathematics news on Phys.org
I'm afraid you will have to expand the terms ##(v-1)^{n}## and some addition theorems on binomials. Perhaps an induction on ##s## can shorten the way.