Deriving Function for Acceleration of Block on a Spring as a Function of Time?

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To derive the acceleration function a(t) for a block attached to a spring, the equation (F - k*s)/m = a is initially proposed, but it is clarified that the correct form should be -k*s/m = a when considering only the spring force. The presence of an external force F complicates the motion, potentially leading to different types of motion such as simple harmonic, damped, or driven oscillations, depending on its nature. To find s as a function of time, one should replace acceleration a with the second derivative of displacement, d²s/dt², and solve the resulting second-order differential equation. The solution will yield s(t), which can then be differentiated to find a(t). Understanding the characteristics of the external force F is crucial for accurately determining the system's behavior.
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Hi fellow physicists,
Suppose a spring with a stiffness k, is attached to wall and with the other side a block with a mass, m, a force F, then pulls the block away from the wall. How do you derive a function for acceleration of the block as a function of time, a(t)?
When trying to solve this I derived the equation: (F-K*s)/m=a but I don't know how to derive a function of s (displacement) as a function of t (to substitute for s in previous equation). The problem seems to be that s(t) is in its turn again a function acceleration which is a function of how far the spring is stretched which is a function of displacement, s :)
Does anyone know how to do this? Thanks
 
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Yes, you are right, acceleration is a function of displacement but you should know what this function is from kinematics.
 
einaap said:
Hi fellow physicists,
Suppose a spring with a stiffness k, is attached to wall and with the other side a block with a mass, m, a force F, then pulls the block away from the wall. How do you derive a function for acceleration of the block as a function of time, a(t)?
When trying to solve this I derived the equation: (F-K*s)/m=a but I don't know how to derive a function of s (displacement) as a function of t (to substitute for s in previous equation). The problem seems to be that s(t) is in its turn again a function acceleration which is a function of how far the spring is stretched which is a function of displacement, s :)
Does anyone know how to do this? Thanks
There should be no F in the equation that you wrote. The only unbalanced force is -ks and this should be equal to ma, So your equation should read -ks/m = a. As you can see, and as paisiello2 pointed out, this shows that the acceleration depends on s. This is a second order differential equation whose solution gives you s as a function of t.
 
No, I think F is an externally applied force so there is an F in the equation.
 
paisiello2 said:
No, I think F is an externally applied force so there is an F in the equation.
Agreed. But if there is an extra applied force in addition to -kx, then it may no longer be simple harmonic motion. The solution of s as a function of t will depend on what F is. for example, if the spring and object are hanging vertically from the ceiling, F would be gravity, and you would still have simple harmonic motion. If F is friction, it would damped harmonic motion, and if F is itself an oscillatory motion, then you would have a driven harmonic oscillator.
 
einaap said:
Hi fellow physicists,
Suppose a spring with a stiffness k, is attached to wall and with the other side a block with a mass, m, a force F, then pulls the block away from the wall. How do you derive a function for acceleration of the block as a function of time, a(t)?
When trying to solve this I derived the equation: (F-K*s)/m=a but I don't know how to derive a function of s (displacement) as a function of t (to substitute for s in previous equation). The problem seems to be that s(t) is in its turn again a function acceleration which is a function of how far the spring is stretched which is a function of displacement, s :)
Does anyone know how to do this? Thanks

Replace acceleration 'a' with ## \frac{d ^2s}{dt^2}## in your equation and solve this differential equation. Then you will find s as a function of t. Then differentiate it twice. You will get the answer. But at first you have to know about the nature of external force F.
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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