Deriving Nilpotent Matrices: I+N^-1 = I - N + N^2 - N^3...

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SUMMARY

The discussion focuses on deriving the inverse of a nilpotent matrix, specifically demonstrating that \((I+N)^{-1} = I - N + N^2 - N^3 + ... + N^{k-1}\) where \(N^k = O\). The user confirms that multiplying \((I+N)\) by the derived expression results in the identity matrix, thus proving the existence of the inverse. This derivation relies on the properties of nilpotent matrices, which have a finite power that results in the zero matrix.

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  • Understanding of nilpotent matrices and their properties
  • Familiarity with matrix operations and identities
  • Knowledge of series expansions in linear algebra
  • Basic concepts of linear transformations
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This discussion is beneficial for students of linear algebra, mathematicians focusing on matrix theory, and anyone interested in the properties and applications of nilpotent matrices.

brydustin
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I am curious how to derive the (I+N)^-1 = I - N + N^2 - N^3 + ... N^(k-1) + 0
Where N^k = O, because we assume that N is nilpotent.

Actually I'm just supposed to show that the inverse always exists (for my homework), but I'm not asking how to find existence, I want to know how this equation is derived (assuming existence).

Thanks...
 
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What happens if you multiply

[tex](I+N)(I-N+N^2-N^3+...N^{k-1})[/tex]
 
AH! Thanks... all the "middle parts fall out

I - N + N - N^2 + N ^2 -... - N^(k-1) +N^(k+1) + N^k

and you are left with Identity, which shows that its the inverse. Thanks :)
 

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