Deriving Oscillating Universe Result: Need Help

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Homework Help Overview

The discussion revolves around deriving a result related to an oscillating universe, specifically the equation R(t) = sqrt(3/lambda)sin(sqrt((3/lambda)ct). The subject area includes cosmology and the Friedmann equations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the derivation of the oscillating universe result, with suggestions to use the Friedmann equation to find parameters K and rho. There is also discussion about the implications of lambda being negative and its effect on the solution.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions about the parameters involved and exploring different interpretations of the derivation process. Some guidance has been offered regarding the use of the Friedmann equation, although there is no consensus on the correct values for K and rho.

Contextual Notes

There are constraints related to the assumptions about lambda and its implications for the nature of the solution, particularly regarding its sign and the resulting behavior of the sine function in the context of the oscillating universe.

p.p
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Does anyone know how to derive the result for an oscillating universe?

R(t)= sqrt(3/lambda)sin(sqrt((3/lambda)ct)

I would appreciate the help on this one
 
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I'm not sure what particular derivation you're after, but presumably in the RW metric there are such K and rho that give such a universe as a solution. You have the solution so why not plug it into the Friedmann equation and solve for K and rho? I think K=-1 and rho=lambda/3 would give this solution.
 
From integral( dR/(sqrt(lambda*R^2/3) - K) = ct
derivation has the initial conditions;
lambda<0
K=-1

Leading to the oscillating universe
 
Sorry, the answer I gave you is not correct. lambda can't be negative because then the argument inside sine would be imaginary and thus it wouldn't be an oscillating solution. But the method should work. Just plug your solution inside the Friedmann eq and find K and rho. There can be many pairs of K and rho that give such a solution.
 

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