Deriving the first-order system for this governing equation

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SUMMARY

The governing equation for the damped nonlinear vibration is defined as mx'' = -8x' - x + 9x^3. To derive a first-order system, the variable u is defined as x', resulting in two first-order differential equations. The critical points (fixed points) are determined where both x' and y' are zero, and the Jacobian matrix is calculated at these points. The eigenvalues of the Jacobian provide insights into the stability and behavior of the solutions near the critical points.

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Homework Statement
Derive first-order system for governing equation of this damped nonlinear vibration; then find and write down the corresponding critical point and Jacobian Matrix.
Relevant Equations
mx'' = -8x' - x + 9x^3
I tried finding the solution of the equation itself but it hasn't helped! Links to concepts would be greatly appreciated...thank you...
 
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Hi,

The term 'governing equation' is slightly misleading in the exercise statement -- I think
mx'' = -8x' - x + 9x^3 is the governing equation.

You sure the composer doesn't mean 'characteristic equation' ?

Deriving a first order system is as simple as defining u = x' and you get a system of two first-order differential equations.
 
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currently said:
Homework Statement:: Derive first-order system for governing equation of this damped nonlinear vibration; then find and write down the corresponding critical point and Jacobian Matrix.
Homework Equations:: mx'' = -8x' - x + 9x^3

I tried finding the solution of the equation itself but it hasn't helped! Links to concepts would be greatly appreciated...thank you...
As @BvU said you can make two first-order equation from the given one by defining an other function y=x'. Then x'' = y'.
The problem does not want you to solve this non-linear system of equations. As I understand, find the critical points (X,Y) (fixed points, equilibrium points) where both x' and y' are zero. What are these points?
Find the Jacobian matrices at the fixed points, and find the eigenvalues.
From the eigenvalues, you get information about the character of solution near the fixed points.
Lissen to
 
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Is that equation really non-linear? I don't think so.

As long as the dependent variable and all its derivatives appear to 1st order only, the equation is linear.
Other than that all I can say is "try Wolfram Alpha"! :smile:
 
rude man said:
Is that equation really non-linear? I don't think so.

As long as the dependent variable and all its derivatives appear to 1st order only, the equation is linear.
Other than that all I can say is "try Wolfram Alpha"! :smile:
The original equation was mx'' = -8x' - x + 9x^3 where x(t) was the dependent variable - a nonlinear second order one. That equation should be replaced by a first-order system of equations, and find the critical point(s) and Jacobian matrix. The system of equation is linearized around the critical point, with coefficients equal to the elements of the Jacobian matrix. From the eigenvalues of the Jacobian at the critical point, one gets information about the kind and stability of the solution near that point.
 
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BvU said:
Hi,

The term 'governing equation' is slightly misleading in the exercise statement -- I think
mx'' = -8x' - x + 9x^3 is the governing equation.

You sure the composer doesn't mean 'characteristic equation' ?

Deriving a first order system is as simple as defining u = x' and you get a system of two first-order differential equations.
Yes, that is the governing equation. Sorry, should have been 'a damped nonlinear vibration' instead of 'this damped nonlinear vibration' and with the equation written below.
 
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ehild said:
The original equation was mx'' = -8x' - x + 9x^3 where x(t) was the dependent variable - a nonlinear second order one. That equation should be replaced by a first-order system of equations, and find the critical point(s) and Jacobian matrix. The system of equation is linearized around the critical point, with coefficients equal to the elements of the Jacobian matrix. From the eigenvalues of the Jacobian at the critical point, one gets information about the kind and stability of the solution near that point.
Yes, I goofed. I was thinking y(x), not x(t). It is nonlinear.
 

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