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B Deriving the gravitational constant factor for lbf

  1. Sep 3, 2016 #1
    I have never had to use the English Engineering System so I am having a bit of a struggle here.

    I understand the concept of an inconsistent system of units. I understand the following 2 statements:
    1lbf = 1lbm x 32 ft/sec^2
    1lbf = 1slug x 1 ft/sec^2

    When given a problem that is asking for the force answer in lbf for an object that is being accelerated at something different than 32 ft/sec^2, i understand why i need to divide the answer by 32 to get the answer in lbf. However, i am stuck in trying to derive the units required for this conversion factor. I can follow why the conversion units are (lbm-ft/lbf-sec^2) once i cancel all the units, but I can not derive those units on my own for some reason. Can someone help out with the steps for figuring out the conversion units? How do you get to lbm-ft/lbf-sec^2 if it was my first time trying to discover a conversion factor?
     
  2. jcsd
  3. Sep 3, 2016 #2

    Dale

    Staff: Mentor

    It is an inconsistent set of units. I don't think that you can derive the conversion factor from first principles.
     
  4. Sep 3, 2016 #3

    Dale

    Staff: Mentor

    You could do it starting from SI units if you know each of those conversion factors.
     
  5. Sep 3, 2016 #4

    jbriggs444

    User Avatar
    Science Advisor

    For historical reasons, the conversion factor is the acceleration of gravity. That is why it is considered a "gravitational" system of units.
     
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