Describing Work Done on an Object through KE

In summary, the question asks for the amount of work done on an electron with initial energy K1 when a force acts on it to decrease its velocity to 1/4th of its original value in the opposite direction. The solution involves substituting the new velocity into the kinetic energy equation to find the work done, which is (-15/16)mv^2. The direction of the particle does not affect the amount of work done, as long as the kinetic energy remains the same. This can be compared to a batter hitting a ball back at the same speed it was thrown, or a brick wall reflecting the ball with no change in speed.

Homework Statement

The question asks about an electron moving with energy K1, then says a force acts on the particle so that its velocity is 1/4th of what it was originally, but in the opposite direction. Find the amount of work done on the particle.

b) Then, decide if the direction of the particle has an effect on your answer.

K1-K2=W
K= 0.5mv^2

The Attempt at a Solution

I solved the solution correctly by substituting v2=(-1/4)v1 to find that the work equals
(-15/16)mv^2. Working on part b), I found that whether I substitute (1/4)v1 or (-1/4)v1, you get the same answer because the quantity is squared, so the work would be the same, which agrees with the answer key. However, I am confused on how this is possible. If I understand this correctly, whether a force causes the electron to slow down to one fourth of its original velocity or whether it is strong enough to actually propel it in the other direction with the same magnitude, because the KE is the same, the work done on the particle is the same.

This is what I am confused about: This seems to be saying that if a baseball is thrown at 100mph toward a batter, it doesn't matter if the batter whiffs or hits it back at 100 mph, because in both instances the batter works just as hard on the ball because in both cases the ball has the same kinetic energy, so K1-K2 equals zero. Is the above accurate? If so, I guess I am still having issues with the definition of work in the physics sense, but it doesn't seem right to me.

This is what I am confused about: This seems to be saying that if a baseball is thrown at 100mph toward a batter, it doesn't matter if the batter whiffs or hits it back at 100 mph, because in both instances the batter works just as hard on the ball because in both cases the ball has the same kinetic energy, so K1-K2 equals zero. Is the above accurate? If so, I guess I am still having issues with the definition of work in the physics sense, but it doesn't seem right to me.

Yes, that's right. The batter does negative work as he decelerates the ball from 100mph to 0, but he compensates for that by doing positive work while accelerating the ball from 0 to 100mph in the other direction. The total is 0, because the only energy the batter spent was in accelerating the bat to the right speed.

If this seems counterintuitive, let's suppose that we replace the batter with a large brick wall. Neglecting loses due to the deformation of the ball, the ball reflects off the wall at exactly the same speed it had before, even though the wall does absolutely nothing.

What is kinetic energy?

Kinetic energy is the energy an object possesses due to its motion. It is a form of energy that is dependent on the mass and velocity of an object.

How is kinetic energy calculated?

Kinetic energy is calculated using the equation KE = 1/2 * m * v^2, where m is the mass of the object and v is the velocity.

What is the relationship between work and kinetic energy?

Work is the transfer of energy from one form to another. When work is done on an object, it results in an increase in the object's kinetic energy.

Can the work done on an object be negative?

Yes, the work done on an object can be negative. This occurs when the force applied to the object is in the opposite direction of its motion, resulting in a decrease in its kinetic energy.

How is the work-energy theorem related to describing work done on an object through kinetic energy?

The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy. This means that the work done on an object can be described by the change in its kinetic energy.

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