- #1

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The problem is: Find the determinant of the following linear transformation.

T(

**v**) = <1, 2, 3> x

**v**(where the x means cross product)

from the plane V given by x + 2y + 3z = 0

So I find the basis vectors

<-2, 1, 0> and <-3, 0, 1>

And I perform the transformation by

T( <-2, 1, 0>) = <-3, 6, 5>

T(<-3, 0, 1>) = < 2, 8, 6>

And so I get the 2 column vectors to be

| -3 2 |

| 6 8 |

| 5 6 |

I know this is so off, but what am I doing wrong exactly?

I can get the others but this one is giving me fits and I know it has to be so simple......