Determine mass of a glider on an air track

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Homework Help Overview

The problem involves determining the mass of a glider on an air track, with a 20.0 g mass attached via a pulley system. The scenario assumes frictionless conditions for both the air track and the pulley, and the string is considered massless. The original poster provides data from a graph, including initial and final velocities and a time interval, and attempts to apply kinematic and dynamic equations to find the glider's mass.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster calculates acceleration and applies Newton's second law to set up equations for both masses involved. They express confusion regarding the results, questioning whether they are calculating the correct mass and if the equations used are appropriate.

Discussion Status

Some participants clarify that certain forces can be disregarded due to their cancellation in the vertical direction, suggesting a focus on horizontal forces. There is acknowledgment of the tension's role in the system, and one participant indicates that the issue has been resolved, although no explicit consensus is reached on the original poster's calculations.

Contextual Notes

The original poster expresses uncertainty about the relevance of the 20.0 g mass in their calculations and notes a discrepancy between their calculated mass and the measured mass of the glider.

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Determine mass of a glider on an air track [solved]

Homework Statement



A 20.0 g mass is stringed to a glider on an air track through a pulley (https://www.physicsforums.com/attachment.php?attachmentid=30478&stc=1&d=1291794499"). I'm supposed to find the mass of said glider, assuming that the air track and pulley are frictionless and the string is massless.

Data from a graph:

V1 = 0.143 m/s
V2 = 0.377 m/s
Δt = 0.24 s

Homework Equations


a = (V2 – V1) / Δt
Fnet = ma

The Attempt at a Solution



a = (V2 – V1) / Δt
= (0.377 – 0.143) / 0.24
= 0.975 m/s2

Mass 1 (https://www.physicsforums.com/attachment.php?attachmentid=30479&stc=1&d=1291794499"):

Fnet = ma
Fn1 + Fg1 + T1 = -m1a
-m1g + T1 = -m1a
-9.8m1 + T1 = -0.975m1
+T = 8.825m1

Mass 2 (https://www.physicsforums.com/attachment.php?attachmentid=30480&stc=1&d=1291794499"):

Fg2 + T2 = m2a
+m2g – T2 = +m2a
(20.0)(9.80) – T2 = 20.0(0.975)
196 – T2 = 19.5
-T2 = -176.5

Final Calculations:

+ T = 8.825m1
(+) – T = -179.84
---------------------
0 = 8.825m1 – 179.84
8.825m1 = 179.84
m1 = 179.84/8.825
= 20 g

When the glider was weighted on a scale, it was said to be 429 g. So I have no idea what I'm doing wrong--am I getting the mass of the "20.0 g mass" here, or is this number just coincidental and irrelevant? Are the equations used incorrect? Thanks for any help.
 
Last edited by a moderator:
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idlackage said:

Homework Statement



Mass 1 (https://www.physicsforums.com/attachment.php?attachmentid=30479&stc=1&d=1291794499"):

Fnet = ma
Fn1 + Fg1 + T1 = -m1a
-m1g + T1 = -m1a
-9.8m1 + T1 = -0.975m1
+T = 8.825m1


You do not have to add in Fn1 and Fg1 because they cancel each other out + they are in the vertical direction. You only need to take into account the horizontal forces(which in this case is the tension from the string).
 
Last edited by a moderator:
The tensions are equal
 
Kikora said:
You do not have to add in Fn1 and Fg1 because they cancel each other out + they are in the vertical direction. You only need to take into account the horizontal forces(which in this case is the tension from the string).

It works now, thank you so much!
 

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