Determine original velocity (kinematics)

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Josh930
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Homework Statement



if a ball hit by a racket at an angle of 3 degrees reaches a height of .330m at its trajectory, how fast was the ball moving when it left the racket?

Homework Equations



d=volt + 1/2at^2
Vf=Vo+at



The Attempt at a Solution



Vox = Vocos(3dgres)
Voy = Vosin(3dgres)

h(max)= Vy=0

so Voy= -at?

i think i have to find the time it takes to reach the max height, then I am lost... please help
 
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Josh930 said:
so Voy= -at?
Sure. Now combine that with your first equation (d=volt + 1/2at^2) and you can solve for the time it takes to reach max height.

That's not the only way to go. You can also invoke another kinematic formula that directly relates distance and velocity for accelerated motion.