How Do You Calculate the Original Velocity of a Cannonball in a Collision?

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SUMMARY

The discussion centers on calculating the original velocity of a 30 kg cannonball that collides with a stationary 150 kg wooden block, resulting in both moving together at 4 m/s. The correct approach utilizes the conservation of momentum formula, represented as m1v1 + m2v2 = (m1 + m2)v'. The original velocity of the cannonball is determined to be 24 m/s, confirming the teacher's answer. The misunderstanding arose from the interpretation of the final velocity post-collision.

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Homework Statement


A 30 kg cannonball strikes a 150 kg stationary wooden block and embeds itself in the block. The block and cannonball move together at 4 m/s. What was the original velocity of the cannonball?

Homework Equations


m1v1=m2v2

The Attempt at a Solution


using the equation i gave i got:

30v=150(4)
v=20

the answer my teacher my teacher gave me was 24 m/s. and i was thinking if you add the '4 m/s' to the velocity i just found it would be '24 m/s'. but i don't know if that was right. i was thinking it might be right because they both moved together after the ball hit the wood for 4 m/s. so is that right? or am i supposed to do something else?

thank you!
sweedeljoseph
 
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The mass after the collision would be the masses of both objects added together since they are now considered to be one object moving at the same velocity.

m1V1 + m2V2 (equals 0) = v'(m1 + m2)

Solve for V1 before
 
so i was right? you add the '4 m/s' to the velocity that i found?
 

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