Determine the average force that the water exerts on the diver

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Homework Help Overview

The problem involves a diver jumping from a height and coming to rest underwater, focusing on calculating the average force exerted by the water on the diver. The subject area includes mechanics and forces in fluid dynamics.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the work-energy principle, specifically the equation mgh = Fd, and question the appropriate height and distance to use in the calculation.

Discussion Status

Some participants have provided guidance on the distance to consider in the calculations, while others have raised questions about the height from which the diver falls. There appears to be a productive exchange regarding the correct interpretation of the problem parameters.

Contextual Notes

There is a discussion about the height of the fall and the distance the diver travels underwater, indicating potential confusion about the setup of the problem.

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A 57.0 kg person jumps from rest off a 11.0 m high tower straight down into the water. Neglect air resistance during the descent. She comes to rest 3.00 m under the surface of the water. Determine the average force that the water exerts on the diver. This force is nonconservative.

i know to use mgh=Fd... i think... but i don't know what distance or height to use or when you are supposed to incorporate the 3.00 m

any help would be apprectiated..
 
Last edited:
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Yeah you're right, mgh = Fd

The distance that the force from the water acts through is 3m, so distance d = 3m.
Stick that into the equation and you are done :D
 
when i do mgh=fd...

(57)(9.8)(11)=f(3)
i get 2048.2 N, but its incorrect. what am i doing wrong?
 
The height dropped in the fall isn't 11m, it is (11+3)m. Does it work now?
 
yes, it worked!
thanks so much :)
 

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