Compute the force the a coloumn of water exerts on an object.

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Homework Help Overview

The discussion revolves around calculating the force exerted by a column of water on a sewer lid, specifically in the context of a significant water column height resulting from a cloudburst. The subject area includes fluid mechanics and pressure calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between pressure and force, questioning how to compute the force based on the height of the water column and the area of the sewer lid. Some participants discuss the implications of gravitational acceleration and the density of water in their calculations.

Discussion Status

There is ongoing exploration of the correct formula to use for calculating the force on the sewer lid, with some participants confirming the inclusion of gravitational acceleration and the density of water in their reasoning. Multiple interpretations of the problem are being discussed, but no consensus has been reached.

Contextual Notes

Participants reference a national exam context for the problem, suggesting that it is designed to be solvable within certain constraints. There is also mention of a drawing that may aid in visualizing the problem, though its details are not provided in the discussion.

IsomDan
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When a cloudburst in the summer of 2011 in Sweden some sewer pipes were
completely filled with water. The sewer lids had been fastened, but in some
places the large amounts of water pushed anyway the sewer lids anyway.

At one point, the water in a sewer pipe, was pushed up 37.5 m above the level of the sewer lid, in a huge water column.
The radius of the sewer lid is 29 cm.

a) Determine the magnitude of the force of the water exerts on the sewer lid

I know that the answer somehow resolves around computing the pressure in the water column and then find the difference in pressure working respectively upwards and downwards on the lid, and the turn that pressure into force via the area of the lid.
 
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But if the water column persists, would there be some kind of force that will keep on working?

It has been given as a national exam a couple of years ago, so I do think that it must be possible to find a solution!
 
And btw, there is a little drawing included.
 

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Your picture makes a good point- the column of water will rise to exactly the height it reaches on the hill side. And the force pushing it up is simply the weight of the water itself. Multiply the height of the water by the cross sectional area and the density of water.
 
Thanks so much for your responses guys

But is that the force working ON the sewer lid?

Isoma
 
HallsofIvy said:
Multiply the height of the water by the cross sectional area and the density of water.

I think you forgot the gravitational acceleration, g..

IsomDan said:
Thanks so much for your responses guys

But is that the force working ON the sewer lid?

Isoma

Respecting Pascal's law, yes it is. :smile:
 
Okay ... So the whole force excerting on the lid is given by

Fwater-on-sewer = ρwater * hcolumn * Asewer * g

?
 
IsomDan said:
Okay ... So the force exerted by the water on the lid is given by

Fwater-on-sewer = ρwater * hcolumn * Asewer * g

?

Yes.
 

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