Determine the direction of vector

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To determine the direction of the vector with components x=7.25 km and y=-3.50 km, the angle is calculated as -25.769 degrees, which indicates a clockwise direction from the +x-axis. However, to express this angle in standard position, it should be converted to a positive angle by subtracting from 360, resulting in 334.231 degrees. The negative y component and positive x component place the vector in the fourth quadrant. A visual sketch can aid in understanding the vector's position. The discussion emphasizes the importance of correctly interpreting angle measurements in physics problems.
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Find the direction of the vector . Let the direction of a vector be the angle that the vector makes with the +x-axis, measured counterclockwise from that axis. x=7.25 km, y=-3.50 km

Please help. I got -25.769, but when I entered it (to the correct sig figs) mastering physics said it was wrong.
 
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Have you tried entering 360 - 25.769 = 334.231?
 
That worked, thank you so much. But why did it have to be subtracted from 360?
 
Do they want the answer in degrees?
 
Yes, but it I got the answer. It had to be subtracted from 360. Thank you anyway.
 
kgianqu2 said:
That worked, thank you so much. But why did it have to be subtracted from 360?

If the y component is negative and the x component is positive, in what quadrant will it be?
Draw a sketch if you don't see it.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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