1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Determine the location of the center of mass of spheres

  1. Oct 9, 2016 #1
    1. The problem statement, all variables and given/known data
    All three disks are made of sheet metal of the same material, and the diameters are 1.0 m , 2.0 m , and3.0 m . Assume that the x-axis has its origin at the left-most point of the left-most object and it points to the right. Part A) Determine the location of the center of mass of the system shown
    . Mazur1e.ch6.p38.jpg

    part B)Repeat the calculation for three solid spheres all made of the same metal and having the same diameters as in part A.
    2. Relevant equations
    m1x1+m2x2+m3x3/m1+m2+m3

    3. The attempt at a solution
    i have gotten the answer for the first part with some help, the answer was 3.5m. i have tried repeating the calculations i took in part A. and got 3.5m again. this is what i did;
    Masses
    4πr2
    mass 1: 4π(0.5)2=3.14159
    mass 2:4π(1)2=12.56637
    mass 3: 4π(1.5)2=28.2743

    center of mass of the system
    3.14159(0.5)+12.56637(1)+28.2743(4.5)/3.14159+12.56637+28.2743
     
  2. jcsd
  3. Oct 9, 2016 #2

    gneill

    User Avatar

    Staff: Mentor

    Sphere mass goes as the volume, not the cross sectional area. How does the volume of a sphere vary with radius?
     
  4. Oct 9, 2016 #3
    thank you i caught my error and got the correct answer of 3.8m
     
  5. Oct 9, 2016 #4

    gneill

    User Avatar

    Staff: Mentor

    You're welcome.

    Rather than pushing around all those digits you could do it symbolically. Let the first sphere's mass be M and have radius r (where r = 1/2 meter). The the masses of the spheres would be M, 8M, 27M (going as the radius cubed). Their center of mass locations would be r, 4r, and 9r. Plugging them into the center of mass formula:

    ##COM = \frac{(M)(r) + (8M)(4r) + (27M)(9r)}{M + 8M + 27M}##

    ##~~~~~~~~~~= \frac{276(r)(M)}{36M}##

    ##~~~~~~~~~~= \frac{23}{3}r##

    And since r is 0.5 m, the result is ##COM = \frac{23}{6}~m \approx 3.83~m##.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Determine the location of the center of mass of spheres
Loading...