Determine the maximum tension in the pendulum rod

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SUMMARY

The maximum tension in a pendulum rod can be calculated using the formula T = ma + mg, where T is the tension, m is the mass of the bob, a is the centripetal acceleration, and g is the acceleration due to gravity. In this case, with a pendulum length of 60 cm and a bob mass of 500 g swinging at a speed of 2.4 m/s, the calculated maximum tension is 4.9 N. The discussion clarified that both the gravitational force and the centripetal force contribute to the total tension in the rod, which is essential for understanding pendulum dynamics.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of centripetal acceleration
  • Familiarity with gravitational force calculations
  • Ability to manipulate equations involving forces
NEXT STEPS
  • Study the derivation of centripetal acceleration formulas
  • Learn about forces acting on pendulums in different states of motion
  • Explore the effects of varying mass and length on pendulum dynamics
  • Investigate real-world applications of pendulum mechanics in clocks
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Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for examples of pendulum motion and force analysis.

nesan
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Homework Statement



A clock’s pendulum is 60 cm long with a bob at the end of mass 500 g. Determine the maximum tension in the pendulum rod when the bob is

b) swinging at a speed of 2.4 m/s

Homework Equations



v^2 / r = ac

The Attempt at a Solution



9.8m/s^2 = g

(2.4)^2 / 0.6 = 9.6m/s^2

9.8 * 0.5 = 4.9N

9.6 * 0.5 = 4.8N

Fnet = 4.9 - 4.8 = 0.1 N

What am I doing wrong? ._.

Thank you.


Okay guys I looked t it from another perspective and ended up wit the right answer.

I added the force of gravity and the tension going up.

But here's a small question. Why do we have to add them? Are they not cancelling each other out? Or is it because the pendulum is balanced ? o.o

So we add both tensions?
 
Last edited:
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hi nesan! :smile:
nesan said:
So we add both tensions?

i'm very worried by your last question :redface:

what did you think the two tensions were? :confused:

(the acceleration is upward

Ftotal = ma, so T - mg = ma, ie T = ma + mg)
 
tiny-tim said:
hi nesan! :smile:


i'm very worried by your last question :redface:

what did you think the two tensions were? :confused:

(the acceleration is upward

Ftotal = ma, so T - mg = ma, ie T = ma + mg)


Yup, I got that last night while in bed thinking. Haha xD

Thank you. :)<3
 

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