Determine the NEW force of attraction between two masses

Click For Summary
SUMMARY

The gravitational force of attraction between two masses can be calculated using the formula Fg = Gm1m2/d². In this discussion, the initial force of attraction is given as 6.88 x 10²¹ N. When the separation distance is tripled and the mass of one object is halved, the new force of attraction can be determined by substituting these values into the equation. The new force is derived by adjusting the distance and mass in the formula, leading to a clear solution based on the principles of gravitational physics.

PREREQUISITES
  • Understanding of Newton's Law of Universal Gravitation
  • Familiarity with gravitational constant (G)
  • Basic algebra for manipulating equations
  • Knowledge of mass and distance relationships in physics
NEXT STEPS
  • Study the implications of changing mass and distance on gravitational force
  • Learn about gravitational force calculations in different contexts
  • Explore the concept of gravitational potential energy
  • Investigate real-world applications of gravitational physics
USEFUL FOR

Students studying physics, educators teaching gravitational concepts, and anyone interested in understanding the mathematical relationships in gravitational attraction.

OverAchiever
Messages
1
Reaction score
0

Homework Statement

Two masses are in space. At a certain separation, the two masses have a force of gravitational attraction of 6.88 x 10 21N Determine the new force of attraction if the separation distance between the two masses is tripled, and mass of one object is reduced by half.

Homework Equations



Fg = Gm1m2/d2

The Attempt at a Solution



Fnew/Fold = Gm1m2/d2Cancel out G,m1, m2
6.88 x 1021 /Fold = 1/d2new divided by 1/d2old

This is as far as I could get and now I don't know what to do. I have some other questions that I would like to ask after I can solve this one if it is not a problem. I have been going through some tough times and missed a lot of class, so now I need to get an understanding of the new concepts I missed by solving these problems
 
Last edited:
Physics news on Phys.org
Welcome to PF!

Hi OverAchiever! Welcome to PF! :wink:

Why not just replace d by 3d, and m1 by m1/2, in the formula? :smile:
 

Similar threads

How to find the equilibrium position of three masses (two of them fixed)?
  • · Replies 4 ·
Replies
4
Views
2K
Understanding the Radial Attraction Force between Two Electric Dipoles
  • · Replies 19 ·
Replies
19
Views
4K
Gravitational Forces between two masses
  • · Replies 5 ·
Replies
5
Views
2K
Coulomb's Law problem: Force of attraction between the two singly charged ions
  • · Replies 3 ·
Replies
3
Views
4K
Find the attractive force of gravity between two objects
  • · Replies 8 ·
Replies
8
Views
2K
Calculating Masses Using Gravitational Force Equations
  • · Replies 5 ·
Replies
5
Views
1K
Irodov- 1.123- Simple conceptual question with two masses connected by a spring
  • · Replies 20 ·
Replies
20
Views
3K
Olympiad dynamics problem with 3 masses and a pulley
  • · Replies 17 ·
Replies
17
Views
3K
Determine the mass of the planet using Newton’s Law of Universal Gravitation
  • · Replies 2 ·
Replies
2
Views
3K
Why did I get two different results for the mass m2?
  • · Replies 19 ·
Replies
19
Views
1K