Determine the rms value of the electric field of the transmitted beam

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SUMMARY

The discussion centers on calculating the rms value of the electric field of a transmitted beam of polarized light with an average intensity of 13.2 W/m² through a polarizer at an angle of 27.5°. The correct approach involves using the equation I = I₀ cos²(θ), leading to an intensity of 11.7085 W/m² after applying Malus's Law. The rms value of the electric field is then calculated using Erms = √(I/(4π × 10^-7) × (3 × 10^8)). The initial miscalculation stemmed from incorrectly omitting the square of the cosine in the intensity calculation.

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  • Knowledge of electric field intensity calculations
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Homework Statement



A beam of polarized light has an average intensity of 13.2 W/m2 and is sent through a polarizer. The transmission axis makes an angle of 27.5° with respect to the direction of polarization. Determine the rms value of the electric field of the transmitted beam.


Homework Equations





The Attempt at a Solution


This is what I have done to try this problem:
I used Erms = square root of: [I(4pi * 10^-7)(3 x 10^8)]
I used I = Iocos^2theta
I = (13.2)(cos27.5)^2
I = 10.3856

According to the homework program I am using, the answer I have gotten is not correct...I am not sure what I am doing wrong. Thanks in advance!
 
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I agree with your value of I=10.4 W/m^2.
Can you post your calculation of Erms?
 
I have finally solved it! So my Erms equation was correct. My intensity was not...
Turns out what I had to do was not square the cos...
so instead of I = Iocos227.5
the equation is:
I = Iocos27.5 = 11.7085

Which I can then plug into the equation for Erms above

Thanks for your help!
 
yeah, I know...but our homework is on a computer program (CAPA), and after using 7 out of 10 tries on this problem I called a classmate and he said that he did it without the cos squared...so I tried it and it was finally marked correct!...not really sure what's going on with this problem!
 

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