Determine the signs of ∆H, ∆G, ∆S for the reaction: N2(g) → 2N(g)

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Start date Apr 10, 2023
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Apr 10, 2023

aquastor

Homework Statement: Determine the signs of ∆H, ∆G, ∆S for the reaction: N2(g) → 2N(g) Assume standard conditions and temperature = 25 oC

Relevant Equations: ∆G=∆H-T∆S

Hello are you able to explain the two incorrect ones. I am not sure how to do this as there is no phase change involved, nor is there a temperature or volume change.

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Apr 12, 2023

DrClaude

Mentor

Which form of nitrogen do you find in nature? What does that tell you about the ΔG of the given reaction?

FAQ: Determine the signs of ∆H, ∆G, ∆S for the reaction: N2(g) → 2N(g)

What is the sign of ∆H for the reaction N2(g) → 2N(g)?

The sign of ∆H for the reaction N2(g) → 2N(g) is positive. This is because breaking the strong triple bond in N2 requires the input of energy, making it an endothermic process.

What is the sign of ∆G for the reaction N2(g) → 2N(g)?

The sign of ∆G for the reaction N2(g) → 2N(g) is also positive under standard conditions. Since the process requires energy input (positive ∆H) and involves an increase in disorder (positive ∆S), ∆G will be positive unless the temperature is extremely high.

What is the sign of ∆S for the reaction N2(g) → 2N(g)?

The sign of ∆S for the reaction N2(g) → 2N(g) is positive. The dissociation of one N2 molecule into two separate N atoms increases the number of particles and the disorder of the system.

Why is ∆H positive for the reaction N2(g) → 2N(g)?

∆H is positive for the reaction N2(g) → 2N(g) because energy is required to break the strong triple bond between the nitrogen atoms in the N2 molecule. This energy input makes the reaction endothermic.

Under what conditions could ∆G become negative for the reaction N2(g) → 2N(g)?

∆G could become negative for the reaction N2(g) → 2N(g) at extremely high temperatures. Since ∆G = ∆H - T∆S, a sufficiently high temperature could make the T∆S term large enough to overcome the positive ∆H, resulting in a negative ∆G.