You release a block from the top of a long, slippery inclined plane of length l that makes an angle θwith the horizontal. The magnitude of the block's acceleration is gsin(θ) .Use the expression you derived in the previous part to determine the speed of the block at the bottom of the incline.
Express your answer in terms of g and the variables m, l, and θ.
The Attempt at a Solution
i know that the correct answer does not depend on "m" so i assumed the equation would be v=l/gsinθ. thats inccorrect and i tried reversing it too and still wrong. i know that they won't be multiplied so i'm unsure the relation