Determine the surface of a cardioid

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SUMMARY

The discussion focuses on determining the surface area of a cardioid defined by the parametric equations x = a(2cos(t) - cos(2t)) and y = a(2sin(t) - sin(2t)). Participants emphasize the importance of identifying the correct limits for the parameter t to perform the integration. Suggestions include sketching the cardioid to visualize its shape and using derivatives to find maximum and minimum x-coordinates. Ultimately, the integral can be set up once the bounds for t are established, allowing for the calculation of the cardioid's area.

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Homework Statement



Consider the cardioid given by the equations:

##x = a(2\cos{t} - \cos{2t})##
##y = a(2\sin{t} - \sin{2t})##

I have to find the surface that the cardioid circumscribes, however, I don't know what limits for ##t## I have to take to integrate over. How can I know that, as I don't know how this shape looks like (or more precisely where it is located)?

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The Attempt at a Solution


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I know how I have to solve the problem once I have the integral bounds, but I don't know how I have to determine these. In similar problems, we could always eliminate cost and sint by using the identity ##cos^2 x + sin^2 x = 1## but neither this nor another way to eliminate the cos, sin seems to work. This makes me think, would it be sufficient if I find the maximum and minimum x-coordinate in function of t using derivatives? Then I would have bounds to integrate over, but this seems like a lot of work.
 
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Math_QED said:
How can I know that, as I don't know how this shape looks like
That's easy ! calculate a few points and connect the dots ! And when things start to repeat, you know you've passed the bound for ##t## :smile:
 
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BvU said:
That's easy ! calculate a few points and connect the dots ! And when things start to repeat, you know you've passed the bound for ##t## :smile:

I have to know what the bound exactly is, so I can use it as my integration bounds.
 
O ?
Math_QED said:
I have to know what the bound exactly is
But you already have an exact expression for the bound :rolleyes:
 
BvU said:
O ?
But you already have an exact expression for the bound :rolleyes:

I don't think I understand what you mean. Can you elaborate?
 
You wrote down the equations in post #1. They exactly define the bound. A bit corny of me, sorry.
Did you make the sketch? Find the domain of ##t## ?

What would your integral look like ?

The section in your textbook/curriculum where this exercise appears: what's it about ?
 
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BvU said:
You wrote down the equations in post #1. They exactly define the bound. A bit corny of me, sorry.
Did you make the sketch? Find the domain of ##t## ?

What would your integral look like ?

The section in your textbook/curriculum where this exercise appears: what's it about ?

It's about integration: definite and indefinite integrals. The next chapter deals with arc length.
 
That answers the last of my three questions. What about the other two ?
let me add another one: do you know two ways to integrate to get the area of a circle ?

I am a bit evasive because I am convinced you will say 'of course' once you have found your way out of this on your own steam...
 
BvU said:
That answers the last of my three questions. What about the other two ?
let me add another one: do you know two ways to integrate to get the area of a circle ?

I am a bit evasive because I am convinced you will say 'of course' once you have found your way out of this on your own steam...

Yes I can find the integral of ##\sqrt{r^2 - x^2}## so that wouldn't be the problem. It's late now but I will try the problem tomorrow again and answer your questions then.
 
  • #10
That's one way. There's a quicker way too. Same way works for the cardioid (but it's admittedly less simple than for a circle -- still an easy integral).

First three (not two) questions in post # 6 are still open ...

And it's ruddy late here too.. :sleep:
 
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  • #11
BvU said:
That's one way. There's a quicker way too. Same way works for the cardioid (but it's admittedly less simple than for a circle -- still an easy integral).

First three (not two) questions in post # 6 are still open ...

And it's ruddy late here too.. :sleep:
Yes I believe you can do x = cos t, y = sin t and then integrate over the correct bounds. I will answer the other questions tomorrow.
 
  • #12
get a good sleep ?
Math_QED said:
x = cos t, y = sin t
Isn't good for an area (only one integrand), but it's in the right direction. You need a factor r in both.

##
\sqrt{r^2 - x^2}\ ## are vertical strips, and I'm trying to lure you towards investigating pie pieces (sectors, so to say). As you picked up correctly.

What would the integral for the cardioid area look like with this approach ?

BvU said:
Did you make the sketch? Find the domain of ##t## ?
 
  • #13
BvU said:
get a good sleep ?
Isn't good for an area (only one integrand), but it's in the right direction. You need a factor r in both.

##
\sqrt{r^2 - x^2}\ ## are vertical strips, and I'm trying to lure you towards investigating pie pieces (sectors, so to say). As you picked up correctly.

What would the integral for the cardioid area look like with this approach ?

I figured out how to solve the problem using your hints. Thanks a lot.
 
  • #14
You're welcome.
 
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