Determine the uniform deceleration of car A

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Homework Help Overview

The problem involves two cars, A and B, that are initially 60 meters apart, with car A traveling at 8.89 m/s and car B at 6.67 m/s. After 45 seconds of braking, the two cars collide, and the task is to determine the uniform deceleration of car A.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss forming equations of motion for both cars using the formula s=ut + 1/2a(t^2). There are attempts to substitute these into the condition of collision but uncertainty remains regarding the correct deceleration value. Some participants also explore the implications of initial positions and velocities.

Discussion Status

There are multiple interpretations of the problem, with some participants suggesting different approaches to calculating the deceleration. Guidance has been offered regarding the setup of equations, but no consensus has been reached on the correct deceleration value.

Contextual Notes

Participants note the importance of unit consistency, particularly regarding the velocities of the cars. There is also mention of the need for clarity in the problem statement regarding the initial conditions and the definition of terms used.

teng125
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cars A and B are d=60m apart and traveling at u(A)=8.89 and u(B)=6.67.knowing that 45s after driver A apply his brake to avoid overtaking B,the two cars collide,determine the uniform deceleration of car A.

i have tried to form eqns using s=ut + 1/2a(t^2) for both cars and substitute into [car A-car B=60] and can't find the answer.
the answer is 0.0395.

pls help...thanx...
 
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If the units of velocities of the cars is m/s, I am geting 0.1965 m/s/s.MP
 
Take the initial position of B to be x= 0. Its position after t seconds is given by xB= 6.67t m. (assuming that by "u(B)= 6.67" you mean "the speed of B is 6.67 m/s. Please be complete.) A's position when t= 0 is x= -60 m. 45 s later, A's position is xA(45)= 8.89(45)= 400.05 m. If we let "a" be A's decceleration, then A's position at time t, t> 45, is given by
xA(t)= 400.05+ 8.89(t-45)- (a/2)(t-45)2.

Just given the information that "the two cars collide" you can't determine A's decceleration. You can calculate the "greatest decceleration so that they collide"- that is, the largest value for a so that xA(t) and xB(t) are equal for some value of t.
 
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i also got the same answer as urs in threat 2
 

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