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Homework Help: Determine the unknown property of a perfect gas

  1. Mar 6, 2012 #1
    1. The problem statement, all variables and given/known data
    a gas in 3-L container at a pressure of 300kpa and a temperature of 700 degrees celsius, and with a mass of .66 g.


    2. Relevant equations

    pv=nrt

    3. The attempt at a solution

    (300)(v)= (.00066 kg)(8.31)(191906 k)

    = 3.51


    im not sure what conversion needs to be done as the correct answer is found to be 1.401 kj/kg.K
     
  2. jcsd
  3. Mar 7, 2012 #2

    rock.freak667

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    Homework Helper


    From the information given and the answer you posted, you are to use PV= mRT to get 'R' for the gas.

    In your calculation you found 'V' as 3.51 when they already gave you V=3 L.
     
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