The discussion focuses on determining the unknown property of a perfect gas using the ideal gas law, specifically the equation PV = nRT. A gas in a 3-L container at a pressure of 300 kPa and a temperature of 700 degrees Celsius with a mass of 0.66 g is analyzed. The calculation initially yielded a volume of 3.51, which is incorrect as the volume is already provided as 3 L. The correct specific gas constant R is calculated to be 1.401 kJ/kg·K.
PREREQUISITESThis discussion is beneficial for students studying thermodynamics, particularly those tackling problems related to the ideal gas law, as well as educators looking for examples of gas property calculations.
thermo15378 said:Homework Statement
a gas in 3-L container at a pressure of 300kpa and a temperature of 700 degrees celsius, and with a mass of .66 g.
Homework Equations
pv=nrt
The Attempt at a Solution
(300)(v)= (.00066 kg)(8.31)(191906 k)
= 3.51
im not sure what conversion needs to be done as the correct answer is found to be 1.401 kj/kg.K