thermo15378 said:Homework Statement
a gas in 3-L container at a pressure of 300kpa and a temperature of 700 degrees celsius, and with a mass of .66 g.
Homework Equations
pv=nrt
The Attempt at a Solution
(300)(v)= (.00066 kg)(8.31)(191906 k)
= 3.51
im not sure what conversion needs to be done as the correct answer is found to be 1.401 kj/kg.K
A perfect gas is an idealized model of a gas that follows the gas laws, which describe the relationships between pressure, volume, and temperature.
To determine the unknown property of a perfect gas, you can use one of the gas laws, such as Boyle's law, Charles's law, or Gay-Lussac's law. These laws can be rearranged to solve for the unknown property.
The assumptions made about a perfect gas include that the gas particles have no volume, there are no intermolecular forces between particles, and the particles move in random, straight-line motion.
In certain conditions, real gases can behave like a perfect gas. For example, at low pressures and high temperatures, the behavior of real gases can be approximated by the behavior of a perfect gas.
The ideal gas law, PV = nRT, can be used to determine the unknown property of a perfect gas by plugging in known values for pressure, volume, and temperature, as well as the gas constant (R) and the number of moles (n). This equation can then be rearranged to solve for the unknown property.