Determine the unknown property of a perfect gas

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thermo15378
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Homework Statement


a gas in 3-L container at a pressure of 300kpa and a temperature of 700 degrees celsius, and with a mass of .66 g.


Homework Equations



pv=nrt

The Attempt at a Solution



(300)(v)= (.00066 kg)(8.31)(191906 k)

= 3.51


im not sure what conversion needs to be done as the correct answer is found to be 1.401 kj/kg.K
 
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thermo15378 said:

Homework Statement


a gas in 3-L container at a pressure of 300kpa and a temperature of 700 degrees celsius, and with a mass of .66 g.


Homework Equations



pv=nrt

The Attempt at a Solution



(300)(v)= (.00066 kg)(8.31)(191906 k)

= 3.51


im not sure what conversion needs to be done as the correct answer is found to be 1.401 kj/kg.K


From the information given and the answer you posted, you are to use PV= mRT to get 'R' for the gas.

In your calculation you found 'V' as 3.51 when they already gave you V=3 L.