Determine the unknown property of a perfect gas

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thermo15378
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Homework Statement



two hundred seventy grams of argon at a pressure of 160kpa and a volume of 1.3 m^3.

Homework Equations


pv=nrt


The Attempt at a Solution



(160^3)(1.3) = (.27)(8.31)(t)

208=2.2437t
t=92.7
 
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thermo15378 said:

Homework Statement



two hundred seventy grams of argon at a pressure of 160kpa and a volume of 1.3 m^3.

Homework Equations


pv=nrt


The Attempt at a Solution



(160^3)(1.3) = (.27)(8.31)(t)

208=2.2437t
t=92.7
Not quite. n is the number of moles. How many moles of argon in .27 kg of argon?

AM
 
0.0067 is what i get for moles but when i plug in the formula I am getting 3649.12 and that cannnot be right.