The discussion revolves around determining an unknown property of argon gas using the ideal gas law, specifically in the context of a given mass, pressure, and volume.
Some participants are exploring the calculations related to the number of moles and questioning the results obtained from the ideal gas law. There is an ongoing examination of the assumptions made regarding the mass of argon and its conversion to moles.
Participants are discussing the mass of one mole of argon and its relevance to the calculations being performed. There is a focus on ensuring the correct interpretation of the variables in the ideal gas law.
Not quite. n is the number of moles. How many moles of argon in .27 kg of argon?thermo15378 said:Homework Statement
two hundred seventy grams of argon at a pressure of 160kpa and a volume of 1.3 m^3.
Homework Equations
pv=nrt
The Attempt at a Solution
(160^3)(1.3) = (.27)(8.31)(t)
208=2.2437t
t=92.7
What is the mass of one mole of Argon?thermo15378 said:0.0067 is what i get for moles but when i plug in the formula I am getting 3649.12 and that cannnot be right.