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Determine the value of this function

  1. May 23, 2007 #1
    1. The problem statement, all variables and given/known data

    A)If 2f(x) - 3f(1/x) = x^2 , determine f(2).

    B)Let f be a function defined by f(n)=2f(n-1) + 3f(n-2), where f(1)=1 and f(2)=2. Determine f(5).

    The attempt at a solution

    I tried to plug in the 2 into all the x's but got the wrong answer. would really appreciate some help to get me understand this topic of functions. not my strong suite at all.
  2. jcsd
  3. May 23, 2007 #2


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    It's best if you show your work [with steps]... even if it is the wrong answer.
  4. May 29, 2007 #3

    for a) i am not sure how to do it, but here is my attempt.

    as far as i understand, f(x) means just plug in a value for x.
    f(2) i think is just x=2

    8/2-3/2 doesn't equal 4.

    so as you can see i am lost.

    b)same thing for be, just put a value given for n.

    f(5)=2f(5-1) + 3f(5-2)

    that answer is also wrong.

    some help would be greatly appreciated.
  5. May 29, 2007 #4


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    "f(x) means just plug in a value for x" ... is okay
    "f(2) i think is just x=2"... ok... but this does not mean that necessarily f(2)=2

    All you can say is
    2f(x) - 3f(1/x) = x^2
    with x=2 is
    2f(2) - 3f(1/2) = 2^2
    which has two unknowns f(2) and f(1/2).
    However, with a clever choice a different value of x, you can get a second equation in the same two unknowns, which produces a system of two equations with two unknowns, which can be solved.
  6. May 29, 2007 #5
    And for (b), calculate f(3) first. Then f(4) and f(5).
  7. May 31, 2007 #6
    sorry, i tried to figure out what you two wanted me to do, but couldn't. i will try to find some other form of help online. thanks again
  8. Jun 16, 2007 #7
    tried really hard to find some form of method that will help me understand but couldn't. these two question for some odd reason are placed at the end of the "introduction to functions" chapter of my precal textbook. they are not part of any homework or test or anything, i was just discombobulated with them and wanted some form of answer to help me learn. if someone could show me how they were solved would be great, they are not an assignment or test so i don't think it would violate any rules. just need some form of look into the steps to solve these. thanks.
  9. Jun 16, 2007 #8


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    did you understand my post?

    Looking back at your first post:
    "as far as i understand, f(x) means just plug in a value for x.
    f(2) i think is just x=2"

    f(x) is rule that says:
    if you give me an x (say 2), I'll give you back a number based on what you gave me. It need not be the same number you gave me.

    ex: f(x)=x+1
    if you give me 1, f(1)=2
    if you give me 2, f(2)=3
    if you give me 3, f(3)=4

    ex: f(x)=(x-2)^2
    if you give me 1, f(1)=1
    if you give me 2, f(2)=0
    if you give me 3, f(3)=1

    In the problem that you posed,
    you don't know explicitly what f(x) is...
    but you are given some hints based on equations that must be satisfied by this hidden function.
    Last edited: Jun 16, 2007
  10. Jun 16, 2007 #9


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    Moe, you pretty much show a lack of understanding of what a function is... f(3) =/= 3 unless f(x)=x, which you definitely don't know (and obviously isn't true, since you proved if it was it wouldn't work!)
  11. Jun 16, 2007 #10
    If you replace x with 1/x through out the equation, you get two equations with f(x) and f(1/x). Eliminate f(1/x) to get f(x) and solve your question.
  12. Jun 16, 2007 #11


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    It has already been pointed out to you that setting x= 2 gives 2f(2)- 3f(1/2)= 4. What do you get if you set x= 1/2? (That's the "clever choice" robphy was talking about.) Now you have two equations for the same two unknown values of f.

    For b), do what phoenixthoth suggested: Since f(x)= 2f(n-1) + 3f(n-2), f(3)=2f(3-2)+ 3f(3-2)= 2f(1)+ 3f(2). What is that equal to? Now do the same thing with f(4) and f(5).
  13. Jun 16, 2007 #12
    i am not sure i understand the concept of the two unknowns. i tried to do it like linear systems but failed. i went through the textbook to try and find another question like these but there are none. does anyone have a link to a good guide that will help me understand the concepts?
  14. Jun 17, 2007 #13
    Thats exactly what it is! 2 equations with 2 unknowns, except your variables are f(2) and f(1/2). We have no clue what these can be, so you need to substitute or eliminate to solve for f(2). The hard part was noticing the trick of letting x=1/2. After that, its all algebra
  15. Jun 17, 2007 #14
    ok. i think the whole f(x) and f(1/x) thing was just confusing me. i replaced them with x and y and did it like robphy advised and got an answer that the back of the book said was correct.



    2x-(9x)/2 - 3/8=4

    so i think f(2)=-7/4.
    did i do it right?
  16. Jun 17, 2007 #15
    Yeah. Thats it.
  17. Jun 17, 2007 #16
    thanks for all the help guys. this question for some reason became an itch for me. i had to solve it. hopefully as i learn more i will be able to better grasp the concepts.
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