Determine the vectors of components

  • Context: MHB 
  • Thread starter Thread starter mathmari
  • Start date Start date
  • Tags Tags
    Components Vectors
Click For Summary
SUMMARY

The discussion focuses on determining the vectors of components for the polynomial vector space $\mathbb{R}[x]$ of degree $\leq 3$ using three bases: $B_1$, $B_2$, and $B_3$. The key inquiry is how to compute $\Theta_{B_1}(b)$ and $\Theta_{B_3}(b)$ for all $b \in B_1$. It is established that $\Theta_{B_1}(b)$ corresponds to the identity matrix's columns, while $\Theta_{B_3}(b)$ relates to the columns of $B_1$. The use of transformation matrices is confirmed as essential for these calculations.

PREREQUISITES
  • Understanding of polynomial vector spaces, specifically $\mathbb{R}[x]$
  • Familiarity with basis vectors and their representations
  • Knowledge of transformation matrices in linear algebra
  • Ability to work with identity matrices and their properties
NEXT STEPS
  • Study the properties of polynomial vector spaces in $\mathbb{R}[x]$
  • Learn about transformation matrices and their applications in linear algebra
  • Explore the concept of basis vectors and their significance in vector spaces
  • Investigate the relationship between different bases in polynomial spaces
USEFUL FOR

Students and professionals in mathematics, particularly those focusing on linear algebra and polynomial vector spaces, as well as educators seeking to deepen their understanding of basis transformations.

mathmari
Gold Member
MHB
Messages
4,984
Reaction score
7
Hey! :o

For the polynomial vector space $\mathbb{R}[x]$ of degree $\leq 3$ we have the following three bases:
$$B_1 = \{1 - X^2 + X^3, X - X^2, 1 - X + X^2, 1 - X\} , \\
B_2 = \{1 - X^3, 1 - X^2, 1 - X, 1 + X^2 - X^3\}, \\
B_3 = \{1, X, X^2, X^3\}$$

How can we determine the following vectors of components $\mathbb{R}^4$ ?

$\Theta_{B_1}(b)$ for all $b \in B_1$

and

$\Theta_{B_3}(b)$ for all $b \in B_1$

Could you give me hint? (Wondering)

Do we use the transformation matrix? If yes, how? (Wondering)
 
Physics news on Phys.org
I have seen the following notes :

$\Theta_{B_1}(b\in B_1)=i$-th comlumn of idenity, since it shown always at itself, and $\Theta_{B_3}(b\in B_1)=i$-th column of $B_1$. Why does this hold? (Wondering)
 

Similar threads

Replies
6
Views
1K
  • · Replies 27 ·
Replies
27
Views
2K
  • · Replies 34 ·
2
Replies
34
Views
2K
Replies
15
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
8
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K