- #1
maluzha
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1. Two transformers T1 and T2 in parallel supply a common load at a lagging pf of 0.8, their per unit impedance are 0.04+j0.09 and 0.01+j0.07 at the same kva ratings of 3000KVA each and load power = 5500KVA
Determine the kva output of each transfromer and power factor
This is how i worked it:
Za=0.04+j0.09
Zb= 0.01+j0.07
Zt=0.05+j0.16
Za/(Za+Zb)= 0.048<66.04/0.168<72.65
=0.286<-6.61
Zb/(za+Zb)=0.071<81.86/0.168<72.65
=0.423<9.21
Sa=5500<-36.86*0.423<9.21 = 2326<-27.65
Sb= 5500<-36.86*0.286<-6.61 = 1573<-43.47
Sa+Sb gives a total of 3899kva which is wrong!
Determine the kva output of each transfromer and power factor
This is how i worked it:
Za=0.04+j0.09
Zb= 0.01+j0.07
Zt=0.05+j0.16
Za/(Za+Zb)= 0.048<66.04/0.168<72.65
=0.286<-6.61
Zb/(za+Zb)=0.071<81.86/0.168<72.65
=0.423<9.21
Sa=5500<-36.86*0.423<9.21 = 2326<-27.65
Sb= 5500<-36.86*0.286<-6.61 = 1573<-43.47
Sa+Sb gives a total of 3899kva which is wrong!
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